Need help

[nirmala]

In my code i try to display the image from database but empty image gets displayed.Please help me to make this code work.Thanks in advance 8^X


<?php $target_path = 'uploads/';

$target_path = $target_path . basename( $_FILES['uploadedfile']['name']);

if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) {
//echo "The file ". basename( $_FILES['uploadedfile']['name']).
" has been uploaded";
$con=mysql_connect("localhost","root","");
mysql_select_db("athenaadminlogin") or die("cannot connect");
$image1= $_FILES['uploadedfile']['name'];
//echo $image;
$query="insert into image values('$image1')";
$result=mysql_query($query) or die('Error1'.mysql_error());

$query="select * from image";
$result1=mysql_query($query) or die('Error'.mysql_error());

while($row = mysql_fetch_array($result1))
{
//echo $row['image'];
$s=$row['image'];

echo "<img src='".$target_path.$s."' />";

}
//echo'<img src="'uploads/.uploadedfile.'" />';
} else{
//echo "There was an error uploading the file, please try again!";
}
?>

 

[user-7256]

There could be a lot going wrong. For one thing I think your path is incorrect. You haven't exactly given us any useful information....

 

[qbert220]

I think it is your echo of the <img> that is wrong. At this point, $target_path has been set to the full uploaded image path (path + uploaded filename), so you'll be echoing the filename twice (path + uploaded filename + filename). If you remove this line:

$target_path = $target_path . basename( $_FILES['uploadedfile']['name']);

then I think it will work better.

If it is still not working, I suggest you use "View Source" in your web browser to look at the generated HTML code and see if that matches your expectation. Also check using FTP that images are being uploaded and put into the expected directory.