[PHP] Scalar value as an array ?

[xrvel]

I got this warning when i run a script on a web server (it works well on my other server). I do not know if this is caused by the server environment or something else.

Warning: Cannot use a scalar value as an array

Here is the line

$name{$j} = charAt($charSets[$j]['sets'], $pos);

Note:
$name is a string.
$charSets is an array
$j and $pos is an integer
charAt is a custom function.

How to fix this warning (actually although it is a warning, it causes an error in my script)?

- Kurniawan.

 

[user-7256]

I'm unfamiliar with the $var{$another_var} notation in PHP. What is that?

 

[xrvel]

I'm unfamiliar with the $var{$another_var} notation in PHP. What is that?

Its for getting a character in a position. $name{0} means first character in $name (string).
On the example, i want to set a character in a position in $name, into other character.

 

[user-7256]

Woah, weird. I can't believe I never knew that. I always thought [$index] was the notation, not {$index}.

Oh well. That's cool.

In regards to your question, I found this post on another forum:

i had $usergroups = 0; somewhere else.
so i guess i was trying to overflow the memory buffer

You might find this helpful too.

Good luck!

 

[xrvel]

Thank you for the link. Its very useful :tu:
I guess my variable does not converted into an array correctly, i will recheck my code