freeflow Established Member โ 15 โ Impact 13 Jun 7, 2008 691 views 2 replies #1 How can I make the "if" statement do something if the mysql query finds a result? $sql = 'SELECT * FROM `Domains` WHERE `status` LIKE \'%delete%\'; if ($sql == ???) { Do something; } Thanks for your help.
How can I make the "if" statement do something if the mysql query finds a result? $sql = 'SELECT * FROM `Domains` WHERE `status` LIKE \'%delete%\'; if ($sql == ???) { Do something; } Thanks for your help.
Tree Established Member โ 15 โ Impact 9 Jun 7, 2008 #2 PHP: <?php $query = mysql_query('SELECT * FROM `Domains` WHERE `status` LIKE \'%delete%\''); if (mysql_num_rows($query) > 0) { # Do something } ?> Last edited: Jun 7, 2008
PHP: <?php $query = mysql_query('SELECT * FROM `Domains` WHERE `status` LIKE \'%delete%\''); if (mysql_num_rows($query) > 0) { # Do something } ?>
P psalzmann Established Member โ 15 โ Impact 17 Jun 7, 2008 #3 PHP: $query = mysql_query(" SELECT * FROM Domains WHERE status LIKE '%delete%' "); if (mysql_num_rows($query) > 0) { while ($res = mysql_fetch_array($query)) { // $res['something']... } }
PHP: $query = mysql_query(" SELECT * FROM Domains WHERE status LIKE '%delete%' "); if (mysql_num_rows($query) > 0) { while ($res = mysql_fetch_array($query)) { // $res['something']... } }