PHP Upload Script

NetworkTown.Net · Nov 20, 2005

Hi i need a php upload script please, i need it simply explaind so i can understand it thanks need it in php quick

Joe · Dec 4, 2005

i have another question

that i hope you can help with...
does php have a script that will record the ip address and file name when an image is uploaded? in a seperate file
e.g.
text.jpg ¦ 111.111.111.111

i hope it can be done

shanee86 · Dec 4, 2005

I think so I own a image hosting site and it inputs the ip with the picture they upload. But I didn't make it lol so have no idea. Also I have one question to ohm how can you make a thumb from a image they user uploads and make it clickable to a full page with the full size image on it I really want to do this for my image host site but have no idea? Thanks.

bquast · Dec 4, 2005

Yeah, there is mysql ways to log ips and flat file ways to log the ip address, always depends on what you want to do.

Joe · Dec 4, 2005

well can anyone tell me? coz this would be really good if i could record the ip?

perhaps shanee86, would you mind sending me your php upload script? and i could have a look through it? i may not be able to make a php script, but i can understand and edit it

Thanks - Joe

Webviper2006 · Dec 8, 2005

You sould know google is a bad search engine. The best ones are Ask Jeeves or Yahoo! The other ones like AOL, or any other one are really bad. So the best just ASK JEEVES.

MikeBigg · Jan 5, 2006

You can get the ip address of your visitor using the following:

$_SERVER["HTTP_X_FORWARDED_FOR"]
$_SERVER["REMOTE_ADDR"]
$_SERVER["HTTP_CLIENT_IP"]

They may or may not all be filled in depending on whether the user is behind a firewall and the settings of the firewall. Also, I believe the first can be a comma separated list of ip addresses. eg 111.222.333.444,222.333.444.555

Usually it is enough to use REMOTE_ADDR.

Remember to grab the date and time as well if you are thinking of tracing back to the image uploader. If the visitor is on a dynamic IP their ISP will need to know this in order to trace the user on that IP at that time.

Once you have the IP address and date and time, you need to save it somewhere. As has been suggested, this would usually be in a database or a text file of some sort.

HTH,

Mike

JFS · Jan 5, 2006

this is what i use

Code:

$resource = fopen("log/views.txt","a");
  fwrite($resource,date("Y"."/"."m"."/"."d h:i:s")." - view - $_REQUEST[id] - $_SERVER[REMOTE_ADDR]\n");
  fclose($resource);

the id is file i pass throw
like www.imghosted.net/view.php?id=file.jpg
the $_REQUEST[id] get's that file.jpg and then i save it on this format:
2005/10/13 11:50:20 - view - Untitled-1.jpg - 193.136.77.119
date - time - type of acess - filename - remote ip
hope it helps you

Wybe · Jan 6, 2006

wouldn't it better to record it in mysql?

allhostz · Jan 6, 2006

$_SERVER["REMOTE_ADDR"]

This is what i use!

MikeBigg · Jan 6, 2006

Wybe said:
wouldn't it better to record it in mysql?

Maybe ... but there is nothing wrong with putting it in a text file. It depends on your application and facilities (ie is mysql available?)

Mike

JFS · Jan 6, 2006

i use it on txt file because it's a litle faster, no latency of mysql.

Palyriot · Mar 2, 2006

I think mysql would be the faster and easier way. Also, it makes things a little bit less cluttered without tons of files for every file uploaded.

nigelwong · Mar 7, 2006

Would anyone know how to edit the script before to give a message like "Please wait, Uploading..." to tell their user the file is uploading?

NetworkTown.Net · Mar 7, 2006

iNod said:

Try this..

PHP:

<?php
if($_POST[finshed] == '1') {
//The directory to upload the images - Must be writable CHMOD 777
$upload_dir = "images/";
//100kb - What size do you want to allow to be uploaded
$max_size = 100000;

if(is_uploaded_file($_FILES['image']['tmp_name']))
{
  $size = $_FILES['image']['size'];

  if($size > $max_size)
  {
    echo "File Too Large. File must be no larger than <b>$max_size</b> bytes.";
    exit();
  }
  $filename = $_FILES['image']['name'];

  if(file_exists($upload_dir.$filename))
  {
    echo "Error: The file named <b>$filename</b> already exists.";
    exit();
  }

  if(move_uploaded_file($_FILES['image']['tmp_name'], $upload_dir.$filename))
  {
    echo "Your image uploaded successfully! Can be found here: <a href='/".$upload_dir.$filename."'>".$upload_dir.$filename."</a>";
    exit();
  }
  else
  {
    echo "There was a problem uploading your file. Please try again.";
    exit();
  }
}
}else{
?>
<html>
<head>
<title>Image upload</title>
</head>

<body>

<form action="upload.php" method="post" enctype="multipart/form-data">
<input type="hidden" name="finshed" value="1">
Image: <input type="file" name="image" size="20"> 
<input type="submit" name="submit" value="Upload">
</form>
</body>
</html> 
<?php } ?>

iNod.

Dose this show the link after upload and

SecondVersion said:
You could always...

PHP:

<?php //30 seconds is the default in php.ini ini_set('max_execution_time', '30'); //2M (megabytes) is the default in php.ini ini_set('upload_max_filesize', '2M'; ?>

More settings:
http://us2.php.net/manual/en/ini.php#ini.list

More info on ini_set:
http://us2.php.net/ini_set

Whats this? what do i name the files ect

edit: just tested the script as show above and it redirects to upload.php but i have not made one i am going to but what do i put in upload.php

NetworkTown.Net · Mar 8, 2006

*bump* any answer

Eric · Mar 8, 2006

As for it refreshing to "upload.php" that's the form action..and yes, it shows a link to the file....anyway:

PHP:

<html>
<head>
<title>Image upload</title>
</head>

<body>

<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" enctype="multipart/form-data">
Image: <input type="file" name="image" size="20"> <input type="submit" name="submit" value="Upload">
</form>

<?php

if(isset($_POST['submit']) && $_POST['submit'] != "")
{
  //The directory to upload the images - Must be writable CHMOD 777
  $upload_dir = "images/";
  //100kb - What size do you want to allow to be uploaded
  $max_size = 100000;

  if(is_uploaded_file($_FILES['image']['tmp_name']))
  {
    $size = $_FILES['image']['size'];

    if($size > $max_size)
    {
      echo 'File Too Large. File must be no larger than <b>'.$max_size.'</b> bytes.';
      exit;
    }
    $filename = $_FILES['image']['name'];

    if(file_exists($upload_dir.$filename))
    {
      echo 'Error: The file named <b>'.$filename.'</b> already exists.';
      exit;
    }
    if(move_uploaded_file($_FILES['image']['tmp_name'], $upload_dir.$filename))
    {
      echo 'Your image uploaded successfully! Can be found here: <a target="_blank" href="/'.$upload_dir.$filename.'">'.$filename.'</a>';
    }
    else
    {
      echo 'There was a problem uploading your file. Please try again.';
    }
  }
}
?>

</body>
</html>

NetworkTown.Net · Mar 8, 2006

SecondVersion said:

As for it refreshing to "upload.php" that's the form action..anyway:

PHP:

<html>
<head>
<title>Image upload</title>
</head>

<body>

<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" enctype="multipart/form-data">
Image: <input type="file" name="image" size="20"> <input type="submit" name="submit" value="Upload">
</form>

<?php

if(isset($_POST['submit']) && $_POST['submit'] != "")
{
  //The directory to upload the images - Must be writable CHMOD 777
  $upload_dir = "images/";
  //100kb - What size do you want to allow to be uploaded
  $max_size = 100000;

  if(is_uploaded_file($_FILES['image']['tmp_name']))
  {
    $size = $_FILES['image']['size'];

    if($size > $max_size)
    {
      echo 'File Too Large. File must be no larger than <b>'.$max_size.'</b> bytes.';
      exit;
    }
    $filename = $_FILES['image']['name'];

    if(file_exists($upload_dir.$filename))
    {
      echo 'Error: The file named <b>'.$filename.'</b> already exists.';
      exit;
    }
    if(move_uploaded_file($_FILES['image']['tmp_name'], $upload_dir.$filename))
    {
      echo 'Your image uploaded successfully! Can be found here: <a target="_blank" href="/'.$upload_dir.$filename.'">'.$filename.'</a>';
    }
    else
    {
      echo 'There was a problem uploading your file. Please try again.';
    }
  }
}
?>

</body>
</html>

As for it refreshing to "upload.php" that's the form action..and yes, it shows a link to the file....anyway:

PHP:

<html>
<head>
<title>Image upload</title>
</head>

<body>

<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" enctype="multipart/form-data">
Image: <input type="file" name="image" size="20"> <input type="submit" name="submit" value="Upload">
</form>

<?php

if(isset($_POST['submit']) && $_POST['submit'] != "")
{
  //The directory to upload the images - Must be writable CHMOD 777
  $upload_dir = "images/";
  //100kb - What size do you want to allow to be uploaded
  $max_size = 100000;

  if(is_uploaded_file($_FILES['image']['tmp_name']))
  {
    $size = $_FILES['image']['size'];

    if($size > $max_size)
    {
      echo 'File Too Large. File must be no larger than <b>'.$max_size.'</b> bytes.';
      exit;
    }
    $filename = $_FILES['image']['name'];

    if(file_exists($upload_dir.$filename))
    {
      echo 'Error: The file named <b>'.$filename.'</b> already exists.';
      exit;
    }
    if(move_uploaded_file($_FILES['image']['tmp_name'], $upload_dir.$filename))
    {
      echo 'Your image uploaded successfully! Can be found here: <a target="_blank" href="/'.$upload_dir.$filename.'">'.$filename.'</a>';
    }
    else
    {
      echo 'There was a problem uploading your file. Please try again.';
    }
  }
}
?>

</body>
</html>

Is there a way of changing it so it shows the url on another page? and is there a way that it shows the url and now the /images/filename.gif and is it possible to show the image too.

NetworkTown.Net · Mar 9, 2006

any answer

Eric · Mar 9, 2006

PHP:

<html>
<head>
<title>Image upload</title>
</head>

<body>

<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" enctype="multipart/form-data">
Image: <input type="file" name="image" size="20"> <input type="submit" name="submit" value="Upload">
</form>

<?php

if(isset($_POST['submit']) && $_POST['submit'] != "")
{
  //The directory to upload the images - Must be writable CHMOD 777
  $upload_dir = "images/";
  //100kb - What size do you want to allow to be uploaded
  $max_size = 100000;

  if(is_uploaded_file($_FILES['image']['tmp_name']))
  {
    $size = $_FILES['image']['size'];

    if($size > $max_size)
    {
      echo 'File Too Large. File must be no larger than <b>'.$max_size.'</b> bytes.';
      exit;
    }
    $filename = $_FILES['image']['name'];

    if(file_exists($upload_dir.$filename))
    {
      echo 'Error: The file named <b>'.$filename.'</b> already exists.';
      exit;
    }
    if(move_uploaded_file($_FILES['image']['tmp_name'], $upload_dir.$filename))
    {
      echo 'Your image uploaded successfully!<br /><br />Preview: <br /><img src="'.$upload_dir.$filename.'" border="0"><br /><br >Link to your image: <a target="_blank" href="/'.$upload_dir.$filename.'">'.$filename.'</a>';
    }
    else
    {
      echo 'There was a problem uploading your file. Please try again.';
    }
  }
}
?>

</body>
</html>

NetworkTown.Net · Mar 9, 2006

SecondVersion said:

PHP:

<html>
<head>
<title>Image upload</title>
</head>

<body>

<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" enctype="multipart/form-data">
Image: <input type="file" name="image" size="20"> <input type="submit" name="submit" value="Upload">
</form>

<?php

if(isset($_POST['submit']) && $_POST['submit'] != "")
{
  //The directory to upload the images - Must be writable CHMOD 777
  $upload_dir = "images/";
  //100kb - What size do you want to allow to be uploaded
  $max_size = 100000;

  if(is_uploaded_file($_FILES['image']['tmp_name']))
  {
    $size = $_FILES['image']['size'];

    if($size > $max_size)
    {
      echo 'File Too Large. File must be no larger than <b>'.$max_size.'</b> bytes.';
      exit;
    }
    $filename = $_FILES['image']['name'];

    if(file_exists($upload_dir.$filename))
    {
      echo 'Error: The file named <b>'.$filename.'</b> already exists.';
      exit;
    }
    if(move_uploaded_file($_FILES['image']['tmp_name'], $upload_dir.$filename))
    {
      echo 'Your image uploaded successfully!<br /><br />Preview: <br /><img src="'.$upload_dir.$filename.'" border="0"><br /><br >Link to your image: <a target="_blank" href="/'.$upload_dir.$filename.'">'.$filename.'</a>';
    }
    else
    {
      echo 'There was a problem uploading your file. Please try again.';
    }
  }
}
?>

</body>
</html>

how do i make it so it shows the url too not just file name hyperlinked to it and so it randomizes the file name

PHP Upload Script

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