PHP/MySQL Help

[freeflow]

I have a link directory and the traffic has increased a lot, so I
would like to add the submitted links directly to a TS, where
I will check them before they are published. At the moment I
receive an email with the link submissions.


What I Would like to do:

1. Check if the link=($variable) starts with http://

2. If it starts with http:// delete the http://

3. Add the link to the TS.

4. If it doesn't contain http:// add it the way it is.

 

[user-7256]

Define TS?

 

[RageD]

Yeah, can't say I'm sure what you mean by TS, but when parsing the link do this:

str_replace("http://","",$_POST['LINK_URL']);

-RageD

 

[freeflow]

Sorry, I meant Tablespace with TS.

 

[Eric]

// Check to see that both: it contains http://, and that the string isn't JUST http://
if (strpos($link, 'http://') !== false AND $link != 'http://')
{
    $link = substr($link, 7);
}

 

[unknowngiver]

I got a similar question if anyone can help
I am considering three cases

1. User enters "www.google.com"
2. User enters "http://www.google.com"
3. User enters "google.com"

in each case, I want to remove the "http://www." part so the final url looks like
"google.com"

Now the tricky part is that the user can enter
"blog.google.com"
or
"http://wwww.blog.google.com"
in which case the final url still should be only
"blog.google.com"

 

[mr-x]

preg_match('/[^.]+\.[^.]+$/', 'http://www.blog.google.com/', $matches);
echo $matches[0]; // google.com/

 

[unknowngiver]

preg_match('/[^.]+\.[^.]+$/', 'http://www.blog.google.com/', $matches);
echo $matches[0]; // google.com/

i want it to show blog.google.com
just strip off http:// and www. if they are entered

 

[eagle12]

This is how I would do it:

$url = str_replace(array("https://","http://","www."),"",strtolower($url));

PHP5:

$url = str_ireplace(array("https://","http://","www."),"",$url);

 

[Eric]

I wouldn't recommend using str_replace for www., what if the domain was: blehwww.com

if ($link != 'http://')
{
	$link = preg_replace('#http[s]?://#i', '', $link);
	$link = preg_replace('#^www\.#i', '', $link);
}

 

[qbert220]

Or just:

$link = preg_replace('#^(https?://)?(www\.)?#i', '', $link);