PHP eval()

miseria · 03-22-2006, 11:15 AM

Hey, Does anyone know how to use the eval function. I wanna output a variable which is stored in a mySQL database but I keep getting this stupid error.

Parse error: syntax error, unexpected T_STRING in /home/.eurypides/npsale/vezor.net/certificate.php(39) : eval()'d code on line 1

I'm guessing there's an error in the entry in the database but i removed the text apart from the variable and still nothing.

PHP Code:

  $certext = stripslashes($row['certext']);

eval("$certext");

Thats part of my PHP for getting the code and eval()ing it.

Thanks

Peter · 03-22-2006, 11:38 AM

try echoing out $certext and ensure that it is valid php code. Never used this function myself but looking at the php.net website it states that it has to be 100% valid php code.

miseria · 03-22-2006, 11:43 AM

Yeah, it works but the variable just reads $variable.. if that makes sense

mikesherov · 03-22-2006, 12:34 PM

the eval function is not what you should use to output variables. Use print() instead. The eval() function evaluates whatever string you put inside of it as PHP code:

print('hello'); //prints to the browser: hello
eval('hello'); //is equivalent to typing "hello" as that LINE OF CODE

print('$cert=2;') // prints to the browser: $cert=2;
eval('$cert=2;') // is the equivalent of typing "$cert=2;" as that LINE OF CODE

eval('$cert=2;');
print($cert);

//will print the value "2" because it is the same as saying:

$cert=2;
print($cert);

miseria · 03-22-2006, 12:59 PM

I get what you're saying Mike, but it still displays "$url" in the text.

$url is the variable in the database.
$certext is the text which the variable is in.

Thanks for the help though Mike

I think it may be the way I've set it up, I set the variable $url first.

1. $url is set
2. Row ($certext) from MySQL database is taken with "$url" within the text.
3. Need to print $certext.

miseria · 03-25-2006, 08:43 AM

I think it may have something to do with my host even. Every page on my website has:

PHP Code:

  $page = "Homepage";

include("head.php");

Then in my head.php file I have:

PHP Code:

  echo "<title>$pagetitle</title>";

Yet in the browser, it displays "$pagetitle" rather than "Homepage". I know it has worked with previous hosts though.

Scott2503 · 03-25-2006, 02:51 PM

You should do this:

PHP Code:

  eval("$certext = stripslashes($row['certext']);");

Try that and post how it works...

miseria · 03-26-2006, 07:03 AM

Get the following error:

Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in /home/.eurypides/npsale/vezor.net/certificate.php on line 38

But thanks anyway

tm · 03-26-2006, 07:07 AM

It could be something simple. try this;

Code:

$certext = stripslashes($row['certext']);
eval($certext);

Scott2503 · 03-26-2006, 08:31 AM

Sorry I meant:

PHP Code:

  eval("$certext = stripslashes(".$row['certext'].");");

miseria · 03-26-2006, 11:15 AM

Nah, still no worky. Not to worry. I'll try a different approach. Thanks anyway Scott

Jim_ · 03-26-2006, 11:32 AM

Quote:

Originally Posted by miseria

PHP Code:

  echo "<title>$pagetitle</title>";

Do this instead:

PHP Code:

  echo "<title>".$pagetitle."</title>";

miseria · 03-26-2006, 11:39 AM

Thanks Jim!

**Eric** · 03-26-2006, 02:02 PM

Quote:

Originally Posted by Scott2503

Sorry I meant:

PHP Code:

  eval("$certext = stripslashes(".$row['certext'].");");

PHP Code:

  eval("\$certext = stripslashes(\$row['certext']);");

Icespadez · 03-27-2006, 07:22 PM

Quote:

Originally Posted by miseria

I think it may have something to do with my host even. Every page on my website has:

PHP Code:

  $page = "Homepage";

include("head.php");

Then in my head.php file I have:

PHP Code:

  echo "<title>$pagetitle</title>";

Yet in the browser, it displays "$pagetitle" rather than "Homepage". I know it has worked with previous hosts though.

Is your variable called $page or $pagetitle? If this is the code you have in your files, there is no variable named $pagetitle.

2knew · 03-27-2006, 09:43 PM

Jim already answered this. post deleted

miseria · 04-02-2006, 01:11 PM

I've been trying to sort this all afternoon. It is still displaying $variable. I've got rid of all the Errors but it is still not working!!

It works when there is just $variable; in the database but I need text with $variable in.

03-22-2006, 11:15 AM	#1 (permalink)
miseria SQLdumpster.com Join Date: Jun 2005 Location: West Sussex, UK Posts: 545 205.50 NP$ (Donate)	PHP eval() Hey, Does anyone know how to use the eval function. I wanna output a variable which is stored in a mySQL database but I keep getting this stupid error. Parse error: syntax error, unexpected T_STRING in /home/.eurypides/npsale/vezor.net/certificate.php(39) : eval()'d code on line 1 I'm guessing there's an error in the entry in the database but i removed the text apart from the variable and still nothing. PHP Code: `$certext = stripslashes($row['certext']); eval("$certext");` Thats part of my PHP for getting the code and eval()ing it. Thanks __________________ !!!!!!! see something you like? Accepting offers for great affiliate websites !!!!!!! Free Databases for your Website \| All Things Playstation 3 Website Design Books \| Music While You Work? \| Computer Gadgets

03-22-2006, 11:43 AM	#3 (permalink)
miseria SQLdumpster.com Join Date: Jun 2005 Location: West Sussex, UK Posts: 545 205.50 NP$ (Donate)	Yeah, it works but the variable just reads $variable.. if that makes sense __________________ !!!!!!! see something you like? Accepting offers for great affiliate websites !!!!!!! Free Databases for your Website \| All Things Playstation 3 Website Design Books \| Music While You Work? \| Computer Gadgets

03-22-2006, 12:59 PM	#5 (permalink)
miseria SQLdumpster.com Join Date: Jun 2005 Location: West Sussex, UK Posts: 545 205.50 NP$ (Donate)	I get what you're saying Mike, but it still displays "$url" in the text. $url is the variable in the database. $certext is the text which the variable is in. Thanks for the help though Mike I think it may be the way I've set it up, I set the variable $url first. 1. $url is set 2. Row ($certext) from MySQL database is taken with "$url" within the text. 3. Need to print $certext. __________________ !!!!!!! see something you like? Accepting offers for great affiliate websites !!!!!!! Free Databases for your Website \| All Things Playstation 3 Website Design Books \| Music While You Work? \| Computer Gadgets

03-25-2006, 08:43 AM	#6 (permalink)
miseria SQLdumpster.com Join Date: Jun 2005 Location: West Sussex, UK Posts: 545 205.50 NP$ (Donate)	I think it may have something to do with my host even. Every page on my website has: PHP Code: `$page = "Homepage"; include("head.php");` Then in my head.php file I have: PHP Code: `echo "<title>$pagetitle</title>";` Yet in the browser, it displays "$pagetitle" rather than "Homepage". I know it has worked with previous hosts though. __________________ !!!!!!! see something you like? Accepting offers for great affiliate websites !!!!!!! Free Databases for your Website \| All Things Playstation 3 Website Design Books \| Music While You Work? \| Computer Gadgets

03-25-2006, 02:51 PM	#7 (permalink)
Scott2503 NamePros Member Join Date: Oct 2005 Posts: 38 9.80 NP$ (Donate)	You should do this: PHP Code: `eval("$certext = stripslashes($row['certext']);");` Try that and post how it works...

03-22-2006, 11:38 AM	#2 (permalink)
Peter Senior Member Join Date: Nov 2003 Location: Scotland Posts: 4,900 0.60 NP$ (Donate)	try echoing out $certext and ensure that it is valid php code. Never used this function myself but looking at the php.net website it states that it has to be 100% valid php code.

03-22-2006, 12:34 PM	#4 (permalink)
mikesherov NamePros Member Join Date: Apr 2005 Posts: 116 134.00 NP$ (Donate)	the eval function is not what you should use to output variables. Use print() instead. The eval() function evaluates whatever string you put inside of it as PHP code: print('hello'); //prints to the browser: hello eval('hello'); //is equivalent to typing "hello" as that LINE OF CODE print('$cert=2;') // prints to the browser: $cert=2; eval('$cert=2;') // is the equivalent of typing "$cert=2;" as that LINE OF CODE eval('$cert=2;'); print($cert); //will print the value "2" because it is the same as saying: $cert=2; print($cert);

03-26-2006, 07:03 AM	#8 (permalink)
miseria SQLdumpster.com Join Date: Jun 2005 Location: West Sussex, UK Posts: 545 205.50 NP$ (Donate)	Get the following error: Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in /home/.eurypides/npsale/vezor.net/certificate.php on line 38 But thanks anyway __________________ !!!!!!! see something you like? Accepting offers for great affiliate websites !!!!!!! Free Databases for your Website \| All Things Playstation 3 Website Design Books \| Music While You Work? \| Computer Gadgets

03-26-2006, 07:07 AM	#9 (permalink)
tm Senior Member Join Date: Nov 2005 Location: on a oil rig just off Ireland Posts: 1,409 374.65 NP$ (Donate)	It could be something simple. try this; Code: $certext = stripslashes($row['certext']); eval($certext); __________________ You design in photoshop, I code into valid XHTML/CSS. Professional PSD, PNG or HTML to tableless XHTML/CSS designs. For more info, send me a PM.

03-26-2006, 08:31 AM	#10 (permalink)
Scott2503 NamePros Member Join Date: Oct 2005 Posts: 38 9.80 NP$ (Donate)	Sorry I meant: PHP Code: `eval("$certext = stripslashes(".$row['certext'].");");`

03-26-2006, 11:15 AM	#11 (permalink)
miseria SQLdumpster.com Join Date: Jun 2005 Location: West Sussex, UK Posts: 545 205.50 NP$ (Donate)	Nah, still no worky. Not to worry. I'll try a different approach. Thanks anyway Scott __________________ !!!!!!! see something you like? Accepting offers for great affiliate websites !!!!!!! Free Databases for your Website \| All Things Playstation 3 Website Design Books \| Music While You Work? \| Computer Gadgets

03-26-2006, 11:39 AM	#13 (permalink)
miseria SQLdumpster.com Join Date: Jun 2005 Location: West Sussex, UK Posts: 545 205.50 NP$ (Donate)	Thanks Jim! __________________ !!!!!!! see something you like? Accepting offers for great affiliate websites !!!!!!! Free Databases for your Website \| All Things Playstation 3 Website Design Books \| Music While You Work? \| Computer Gadgets

03-27-2006, 09:43 PM	#16 (permalink)
2knew NamePros Member Join Date: Oct 2005 Posts: 191 3,301.75 NP$ (Donate)	Jim already answered this. post deleted

04-02-2006, 01:11 PM	#17 (permalink)
miseria SQLdumpster.com Join Date: Jun 2005 Location: West Sussex, UK Posts: 545 205.50 NP$ (Donate)	I've been trying to sort this all afternoon. It is still displaying $variable. I've got rid of all the Errors but it is still not working!! It works when there is just $variable; in the database but I need text with $variable in. __________________ !!!!!!! see something you like? Accepting offers for great affiliate websites !!!!!!! Free Databases for your Website \| All Things Playstation 3 Website Design Books \| Music While You Work? \| Computer Gadgets Last edited by miseria; 04-02-2006 at 01:18 PM.

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