Php - Show Today's Entry From Text File

$day = date('D'); // Wed
$dayfile = sprintf('/path/to/%s.txt', $day); // /path/to/Wed.txt

if (file_exists($dayfile))
{
    echo file_get_contents($dayfile);
}

$day = date('D'); // Wed

$daylines = array(
  'Mon' => 'output for Monday',
  'Wed' => 'output to display on Wednesdays',
  'Fri'  => 'output for Friday',
); // you get the idea here...

if (isset($daylines[$day]))
{
    echo $daylines[$day];
}

$lines = file('/path/to/365dayfile.txt', FILE_IGNORE_NEW_LINES | FILE_SKIP_EMPTY_LINES);
$dayofyear = date('z'); // today is 166th day of the year
print $lines[$dayofyear];  // will print the 167th line?

Monday June 14 2010 Mark 3
Tuesday June 15 2010 Mark 4
Wednesday June 16 2010 Mark 5
Thursday June 17 2010 Mark 6
Friday June 18 2010 Mark 7

<?php
$fp = fopen("mobile-biblereading.txt", "r");
while ($fileinfo = fscanf($fp, "%s %s %s %s %s %s\n")) {
	list($day, $month, $date, $year, $book, $chapter) = $fileinfo;
	if ("$day, $month $date, $year" == date("l, F d, Y")) {
		echo "$day, $month $date, $year - $book $chapter";
	}
}
fclose($fp);
?>

$regex = sprintf('/%s(.*)/', date('l, F j, Y, '));

if (preg_match($regex, file_get_contents('/path/eachday.txt'),$match))
{
	print $match[1];
}