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Old 12-30-2007, 06:09 PM   · #1
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Cool Amazing Math Trick
Here is a math trick so unbelievable that it will stump you.

1. Grab a calculator. (you won't be able to do this one in your head)
2. Key in the first three digits of your phone number (NOT the area code)
3. Multiply by 80
4. Add 1
5. Multiply by 250
6. Add the last 4 digits of your phone number
7. Add the last 4 digits of your phone number again.
8. Subtract 250
9. Divide number by 2

Do you recognize the answer?


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Old 12-30-2007, 08:16 PM   · #2
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it works lol
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Old 12-30-2007, 08:20 PM   · #3
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Old 12-30-2007, 08:38 PM   · #4
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lol, now that was neat.
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Old 12-30-2007, 08:47 PM   · #5
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Whoah...now why does that work?

x is first few digits, y is last few digits

80x+1
(80x+1)*250 = 20000x+250
20000x+250+y
20000x+250+y+y=20000x+250+2y
20000x+250+2y-250=20000x+2y
(20000x+2y)/2=10000x+y

That makes sense, huh. Given that the phone number is the last four digits plus 10,000 times the first three digits (because it is 4 decimal places over).

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Old 12-30-2007, 09:28 PM   · #6
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WOW that was nice

x = (x1 * 80) + 1 * 250 + x2 + x2 - 250 / 2
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Old 12-30-2007, 09:31 PM   · #7
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wow cool. Thanks for sharing
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Old 12-30-2007, 09:46 PM   · #8
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Originally Posted by Frikkle
80x+1
(80x+1)*250 = 20000x+250
20000x+250+y
20000x+250+y+y=20000x+250+2y
20000x+250+2y-250=20000x+2y
(20000x+2y)/2=10000x+y



Oh, why didn't you just say that in the first place?
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Old 12-31-2007, 04:00 AM   · #9
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works.
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Old 12-31-2007, 05:58 AM   · #10
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Wow. It even works with a hong kong phone number.
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Old 12-31-2007, 08:48 AM   · #11
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x = (x1 * 80) + 1 * 250 + x2 + x2 - 250 / 2

Is there a shorter mathematical expression for this? Or is that the shortest possible?
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Old 03-06-2008, 08:46 AM   · #12
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wont work if either in your last 4 digits, or the first 3 digits...the FIRST number is "0"
for example my last 4 digits were "0486" so it didnt work
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Old 03-06-2008, 05:39 PM   · #13
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Originally Posted by dgridley
x = (x1 * 80) + 1 * 250 + x2 + x2 - 250 / 2

Is there a shorter mathematical expression for this? Or is that the shortest possible?

This one is shorter: x = your phone number.


Originally Posted by unknowngiver
wont work if either in your last 4 digits, or the first 3 digits...the FIRST number is "0"
for example my last 4 digits were "0486" so it didnt work

You did something wrong. (I tried it with xxx-0486 and it worked.) The only way it wouldn't "work" would be if the very first number is 0 which it can't be (I think).
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Old 03-06-2008, 09:02 PM   · #14
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That's Pretty Cool.

If you let x = first digits of phone number, y = last 4 digits of phone number.
[(80x + 1)250 + 2y - 250]/2
[20000x + 250 -250 + 2y]/2
[20000x + 2y]/2
10000x + y

So this does make sense, since you are effectively shifting your x value by a factor of 10000 or 4 zero places. This is similar to how a computer does addition and subtraction back in the old days when memory was at a premium.

Of course any leading zeros in the x place would make this equation produce the wrong result. Maybe that's why all phone numbers don't begin with zeros.

Originally Posted by dgridley
Here is a math trick so unbelievable that it will stump you.

1. Grab a calculator. (you won't be able to do this one in your head)
2. Key in the first three digits of your phone number (NOT the area code)
3. Multiply by 80
4. Add 1
5. Multiply by 250
6. Add the last 4 digits of your phone number
7. Add the last 4 digits of your phone number again.
8. Subtract 250
9. Divide number by 2

Do you recognize the answer?

Last edited by allabout42 : 03-06-2008 at 09:05 PM.
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Old 03-06-2008, 09:04 PM   · #15
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Pretty cool! Gave me a chuckle.
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Old 03-06-2008, 09:45 PM   · #16
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And who would find the time to discover an equation like this?

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Old 03-06-2008, 11:20 PM   · #17
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