Getting a parse error on line 144 help please

co.ador · 06-28-2009, 09:50 AM

PHP Code:

  <?php

$query = "SELECT * FROM menu WHERE id IN (1, 2, 3, 4)"; 

// execute query 

$result = mysql_query($query) or die ("Error in query: $query. ".mysql_error()); 

// see if any rows were returned 

if (mysql_num_rows($result) > 0) { 

    // yes 

    // print them one after another 

    echo '<table  class="felo">'; 

    echo "<tr>";

????: NamePros.com http://www.namepros.com/programming/593011-getting-parse-error-line-144-help.html
    echo'<td width="800" height="100%" bgcolor="#FFFFFF" class="quelo">'; 

    while($row2 = mysql_fetch_row($result)) {

        $get = '?';

        $delimiter = '';

        foreach($ids as $id){

????: NamePros.com http://www.namepros.com/showthread.php?t=593011
            $get .= 'id[]=' . $id . $delimiter;

            $delimiter = '&';

        }

        echo <<<ROW // line 144--

            <table class="trelo" >

                <tr>

                    <td width="152" rowspan="2" class="cebo">

                        <h3 align="center"><a href="itemdetails.php?{$get}> {$row2[3]}</a> </h3>

                        <p>

                            <a href="#"><img src="{$row2[0]}" width="140" height="160" alt="product" style=" border-color:#FF6600; border:thin; border-style:solid;"/></a>

                        </p>

                    </td>

                </tr>

            </table> 

ROW;

}

    echo "</td>";

    echo "</tr>";

    echo "</table>";

}

What could that be I have research but from my limited view I don't see any mistake.

bbosh · 06-28-2009, 02:28 PM

ensure there is absolutely no whitespace after <<<ROW (except the new line). Remove the comment.

If you get unexpected $end error, replace echo with print.

-Brendon.

06-28-2009, 09:50 AM	THREAD STARTER #1 (permalink)
co.ador New Member Join Date: Jun 2009 Posts: 2	Getting a parse error on line 144 help please PHP Code: <?php $query = "SELECT * FROM menu WHERE id IN (1, 2, 3, 4)"; // execute query $result = mysql_query($query) or die ("Error in query: $query. ".mysql_error()); // see if any rows were returned if (mysql_num_rows($result) > 0) { // yes // print them one after another echo '<table class="felo">'; echo "<tr>"; ????: NamePros.com http://www.namepros.com/programming/593011-getting-parse-error-line-144-help.html echo'<td width="800" height="100%" bgcolor="#FFFFFF" class="quelo">'; while($row2 = mysql_fetch_row($result)) { $get = '?'; $delimiter = ''; foreach($ids as $id){ ????: NamePros.com http://www.namepros.com/showthread.php?t=593011 $get .= 'id[]=' . $id . $delimiter; $delimiter = '&'; } echo <<<ROW // line 144-- <table class="trelo" > <tr> <td width="152" rowspan="2" class="cebo"> <h3 align="center"><a href="itemdetails.php?{$get}> {$row2[3]}</a> </h3> <p> <a href="#"><img src="{$row2[0]}" width="140" height="160" alt="product" style=" border-color:#FF6600; border:thin; border-style:solid;"/></a> </p> </td> </tr> </table> ROW; } echo "</td>"; echo "</tr>"; echo "</table>"; } What could that be I have research but from my limited view I don't see any mistake.

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06-28-2009, 02:28 PM	#2 (permalink)
bbosh NamePros Member Join Date: Aug 2008 Posts: 44	ensure there is absolutely no whitespace after <<<ROW (except the new line). Remove the comment. If you get unexpected $end error, replace echo with print. -Brendon.

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