how to display updated data after update?

baris22 · 11-09-2008, 06:19 AM

hello all,

I am trying to lerarn how to update database. Everything is fine but after the update is done it is still showing the content which was before the update.

if i put the browser off and on again there is no problem, it is showing the updated content.

What can i do to show the updated content after pressing submit?

Thanks

PHP Code:

  
<?php

$host="localhost"; // Host name 

$username=""; // Mysql username 

$password=""; // Mysql password 

$db_name="test"; // Database name 

$tbl_name="test_mysql"; // Table name 

 
mysql_connect("$host", "$username", "$password")or die("cannot connect"); 

mysql_select_db("$db_name")or die("cannot select DB");

 
$sql="SELECT * FROM $tbl_name";

$result=mysql_query($sql);

$count=mysql_num_rows($result);

?>

<table width="500" border="0" cellspacing="1" cellpadding="0">

<form name="form1" method="post" action="">

????: NamePros.com http://www.namepros.com/programming/531792-how-display-updated-data-after-update.html
<tr> 

<td>

<table width="500" border="0" cellspacing="1" cellpadding="0">

 
 
<tr>

<td align="center"><strong>Id</strong></td>

<td align="center"><strong>Name</strong></td>

<td align="center"><strong>Lastname</strong></td>

</tr>

<?php

while($rows=mysql_fetch_array($result)){

?>

<tr>

<td align="center"><? $id[]=$rows['id']; ?><? echo $rows['id']; ?></td>

????: NamePros.com http://www.namepros.com/showthread.php?t=531792
<td align="center"><input name="name[]" type="text" id="name" value="<? echo $rows['name']; ?>"></td>

<td align="center"><input name="lastname[]" type="text" id="lastname" value="<? echo $rows['lastname']; ?>"></td>

</tr>

<?php

}

?>

<tr>

<td colspan="4" align="center"><input type="submit" name="Submit" value="Submit"></td>

</tr>

</table>

</td>

</tr>

</form>

</table>

<?php

// Check if button name "Submit" is active, do this 

if($Submit){

for($i=0;$i<$count;$i++){

$sql1="UPDATE $tbl_name SET name='$name[$i]', lastname='$lastname[$i]' WHERE id='$id[$i]'";

$result1=mysql_query($sql1);

}

}

 
if($result1){

echo "<h4>Updated</h4>";

}

mysql_close();

?>

Ok sorted,

instead of

PHP Code:

  echo "<h4>Updated</h4>";

i added

PHP Code:

  echo "<meta http-equiv=\"refresh\" content=\"0\">";

qbert220 · 11-11-2008, 08:42 AM

I would move the update code to before the select query:

Code:

<?php
$host="localhost"; // Host name
$username=""; // Mysql username
$password=""; // Mysql password
$db_name="test"; // Database name
$tbl_name="test_mysql"; // Table name

mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");

// Check if button name "Submit" is active, do this
if($Submit){
  for($i=0;$i<$count;$i++){
    $sql1="UPDATE $tbl_name SET name='$name[$i]', lastname='$lastname[$i]' WHERE id='$id[$i]'";
    $result1=mysql_query($sql1);
  }
} 
$sql="SELECT * FROM $tbl_name";
$result=mysql_query($sql);
$count=mysql_num_rows($result);
?>

11-09-2008, 06:19 AM	THREAD STARTER #1 (permalink)
baris22 NamePros Member Join Date: Jan 2007 Posts: 98	how to display updated data after update? hello all, I am trying to lerarn how to update database. Everything is fine but after the update is done it is still showing the content which was before the update. if i put the browser off and on again there is no problem, it is showing the updated content. What can i do to show the updated content after pressing submit? Thanks PHP Code: <?php $host="localhost"; // Host name $username=""; // Mysql username $password=""; // Mysql password $db_name="test"; // Database name $tbl_name="test_mysql"; // Table name mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $sql="SELECT * FROM $tbl_name"; $result=mysql_query($sql); $count=mysql_num_rows($result); ?> <table width="500" border="0" cellspacing="1" cellpadding="0"> <form name="form1" method="post" action=""> ????: NamePros.com http://www.namepros.com/programming/531792-how-display-updated-data-after-update.html <tr> <td> <table width="500" border="0" cellspacing="1" cellpadding="0"> <tr> <td align="center"><strong>Id</strong></td> <td align="center"><strong>Name</strong></td> <td align="center"><strong>Lastname</strong></td> </tr> <?php while($rows=mysql_fetch_array($result)){ ?> <tr> <td align="center"><? $id[]=$rows['id']; ?><? echo $rows['id']; ?></td> ????: NamePros.com http://www.namepros.com/showthread.php?t=531792 <td align="center"><input name="name[]" type="text" id="name" value="<? echo $rows['name']; ?>"></td> <td align="center"><input name="lastname[]" type="text" id="lastname" value="<? echo $rows['lastname']; ?>"></td> </tr> <?php } ?> <tr> <td colspan="4" align="center"><input type="submit" name="Submit" value="Submit"></td> </tr> </table> </td> </tr> </form> </table> <?php // Check if button name "Submit" is active, do this if($Submit){ for($i=0;$i<$count;$i++){ $sql1="UPDATE $tbl_name SET name='$name[$i]', lastname='$lastname[$i]' WHERE id='$id[$i]'"; $result1=mysql_query($sql1); } } if($result1){ echo "<h4>Updated</h4>"; } mysql_close(); ?> Ok sorted, instead of PHP Code: `echo "<h4>Updated</h4>";` i added PHP Code: `echo "<meta http-equiv=\"refresh\" content=\"0\">";` __________________ Rapidme (rapidshare application) Last edited by baris22; 11-09-2008 at 08:02 AM.

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