More than one ajax request?

omegapandor · 07-14-2008, 03:58 PM

I'm just learning about the XmlHttpRequest object. I have a basic demonstration for myself built, but I can only use it once. After pressing the "submit" button, I have to exit out of firefox before trying it again. If I press the button more than once, nothing happens.

I think I need to restart the object for accepting requests at the end of my code or something. . .but I don't know how.

Pls. . .helps. . .

Code:

createobjectandstuff()
{

req.onreadystatechange = function()
		{ 
			document.ajax.txt.value="Attacking...";
			if(req.readyState == 4)
			{
				if(req.status == 200)
				{
					document.ajax.txt.value=req.responseText;	
				}	
				else	
				{
					document.ajax.txt.value="Error: returned status code " + req.status + " " + req.statusText;
				}	
			} 
		}; 
		req.open("GET", "fileiwantoget.php", true); 
		req.send(null);
	}

nasaboy007 · 07-14-2008, 04:52 PM

i'm no ajax expert, but whenever i've used it i've always called the function with onkeyup, onchange, onblur, or onfocus.

if you look on w3schools.com they have the basic framework that almost all ajax scripts need (which i don't see in your code, but then again you could be doing some other method i don't know about).

omegapandor · 07-14-2008, 05:31 PM

I just realized that my submit button creates the object every time. I assume this is bad and has something to do with the problem.

07-14-2008, 03:58 PM	#1 (permalink)
omegapandor NamePros Regular Join Date: May 2008 Posts: 240 611.95 NP$ (Donate)	More than one ajax request? I'm just learning about the XmlHttpRequest object. I have a basic demonstration for myself built, but I can only use it once. After pressing the "submit" button, I have to exit out of firefox before trying it again. If I press the button more than once, nothing happens. I think I need to restart the object for accepting requests at the end of my code or something. . .but I don't know how. Pls. . .helps. . . Code: createobjectandstuff() { req.onreadystatechange = function() { document.ajax.txt.value="Attacking..."; if(req.readyState == 4) { if(req.status == 200) { document.ajax.txt.value=req.responseText; } else { document.ajax.txt.value="Error: returned status code " + req.status + " " + req.statusText; } } }; req.open("GET", "fileiwantoget.php", true); req.send(null); } __________________ Are you tired of viruses and popups? Use Firefox!

07-14-2008, 04:52 PM	#2 (permalink)
nasaboy007 Senior Member Join Date: Jul 2005 Location: NJ Posts: 1,112 1,454.30 NP$ (Donate)	i'm no ajax expert, but whenever i've used it i've always called the function with onkeyup, onchange, onblur, or onfocus. if you look on w3schools.com they have the basic framework that almost all ajax scripts need (which i don't see in your code, but then again you could be doing some other method i don't know about). __________________ Hacksar.com - Your source for random computer tips and tricks! MySiteMemberships.com - Keep track of your site registration information! Like my post? Rep is appreciated!

07-14-2008, 05:31 PM	#3 (permalink)
omegapandor NamePros Regular Join Date: May 2008 Posts: 240 611.95 NP$ (Donate)	I just realized that my submit button creates the object every time. I assume this is bad and has something to do with the problem. __________________ Are you tired of viruses and popups? Use Firefox!

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