PHP Help - I must be over looking something

jdk · 07-30-2007, 11:56 AM

I have been staring at this since last night and for some reason I must be overlooking something. I have had no problems in the past but for some reason this one is has me stumped.

Code removed b/c project has not officially been released I am working on.

cef · 07-30-2007, 06:36 PM

Replace this line

PHP Code:

                                      $pageprev = $page=$page-1;

With this

PHP Code:

                                      $pageprev = $page-1;

and

PHP Code:

                                      $pagenext = $page=$page+1;

With this

PHP Code:

                                      $pagenext = $page+1;

In both cases you're inadvertently setting $page in the code along with $pageprev and $pagenext.

Note that the second case ($pagenext) doesn't manifest an error for you because you no longer access the $page variable after that code. But it's a logic error nonetheless, and one day you might just need to access $page somewhere after creating the prev/next links.

jdk · 07-30-2007, 06:43 PM

Thanks I also had to remove the

PHP Code:

  $page++;

I must have added in there.

cef · 07-30-2007, 07:02 PM

Ah yeah. I commented that out in the test code as well and forgot to mention it.

07-30-2007, 11:56 AM	#1 (permalink)
jdk Senior Member Join Date: Jul 2004 Location: Florida Posts: 1,223 306.40 NP$ (Donate)	[RESOLVED] PHP Help - I must be over looking something I have been staring at this since last night and for some reason I must be overlooking something. I have had no problems in the past but for some reason this one is has me stumped. Code removed b/c project has not officially been released I am working on. Last edited by jdk; 07-30-2007 at 06:44 PM. Reason: RESOLVED

07-30-2007, 06:36 PM	#2 (permalink)
cef NamePros Regular Join Date: May 2004 Location: NYC Posts: 236 76.50 NP$ (Donate)	Replace this line PHP Code: `$pageprev = $page=$page-1;` With this PHP Code: `$pageprev = $page-1;` and PHP Code: `$pagenext = $page=$page+1;` With this PHP Code: `$pagenext = $page+1;` In both cases you're inadvertently setting $page in the code along with $pageprev and $pagenext. Note that the second case ($pagenext) doesn't manifest an error for you because you no longer access the $page variable after that code. But it's a logic error nonetheless, and one day you might just need to access $page somewhere after creating the prev/next links.

07-30-2007, 06:43 PM	#3 (permalink)
jdk Senior Member Join Date: Jul 2004 Location: Florida Posts: 1,223 306.40 NP$ (Donate)	Thanks I also had to remove the PHP Code: `$page++;` I must have added in there.

07-30-2007, 07:02 PM	#4 (permalink)
cef NamePros Regular Join Date: May 2004 Location: NYC Posts: 236 76.50 NP$ (Donate)	Ah yeah. I commented that out in the test code as well and forgot to mention it.

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