is this the best way ?

champ_rock · 05-14-2007, 07:18 AM

hi

i am trying to create a simple adsense rotation script which would display the ads in a certain ratio

if i have to distribute the ads in 50-50% ratio then i would follow this

Code:

<?php 
$rand = rand(1,2);
if ($rand == 1) 
print 'adsense code 1';

elseif ($rand == 2) 
print 'adsense code 2;
?>

but the problem is suppose i want to distribute the ads into a certain ratio of say 70-30%
then should i do it manually by using

Code:

rand(1,2,3,4,5,6,7,8,9,0)

and then using if statement to print out "code 1" 7 times and "code 2" 3 times?

or is there any better and more efficient way to do this all?

JFS · 05-14-2007, 08:00 AM

Quote:

Originally Posted by champ_rock

Code:

<?php 
$rand = rand(1,2);
if ($rand == 1) 
print 'adsense code 1';

elseif ($rand == 2) 
print 'adsense code 2;
?>

a more eficient way would be

Code:

$adsense['1']= "code here";
$adsense['2']= "code here";
$rand = rand(1,2);


echo $adsense[$rand];

if you use rand(1,9) it gives you a random number between 1 and 9.
if you want percentages and want them precise you should use a database.

cef · 05-14-2007, 12:11 PM

Here's a function that returns 0 or 1 based on which side of a user-definable threshold the random number ends up on. Explanation after the code:

PHP Code:

  function rand_threshold($threshold)

{

     return mt_rand(1,100) <= $threshold ? 0 : 1;

}

The function returns 0 if the random value is less than or equal to the threshold passed in as a parameter, or 1 if it's greater.

So...if you call the function as such:

PHP Code:

  $rand = rand_threshold(30);

$rand will be 0 30% of the time, and 1 70% of the time. You can use the returned values as indexes into the array of ad codes.

If you want the opposite to happen, e.g. the SECOND ad code to come up only 30% of the time, just invert the threshold:

PHP Code:

  $rand = rand_threshold(70);

For the 50/50 scenario you first outlined, it should be obvious what to do

PHP Code:

  $rand = rand_threshold(50);

05-14-2007, 07:18 AM	#1 (permalink)
champ_rock Senior Member Join Date: Oct 2006 Location: http://akshayjain.org Posts: 2,768 8,037.05 NP$ (Donate)	is this the best way ? hi i am trying to create a simple adsense rotation script which would display the ads in a certain ratio if i have to distribute the ads in 50-50% ratio then i would follow this Code: <?php $rand = rand(1,2); if ($rand == 1) print 'adsense code 1'; elseif ($rand == 2) print 'adsense code 2; ?> but the problem is suppose i want to distribute the ads into a certain ratio of say 70-30% then should i do it manually by using Code: rand(1,2,3,4,5,6,7,8,9,0) and then using if statement to print out "code 1" 7 times and "code 2" 3 times? or is there any better and more efficient way to do this all? __________________ Akshay Jain ......................

05-14-2007, 12:11 PM	#3 (permalink)
cef NamePros Regular Join Date: May 2004 Location: NYC Posts: 236 76.50 NP$ (Donate)	Here's a function that returns 0 or 1 based on which side of a user-definable threshold the random number ends up on. Explanation after the code: PHP Code: `function rand_threshold($threshold) { return mt_rand(1,100) <= $threshold ? 0 : 1; }` The function returns 0 if the random value is less than or equal to the threshold passed in as a parameter, or 1 if it's greater. So...if you call the function as such: PHP Code: `$rand = rand_threshold(30);` $rand will be 0 30% of the time, and 1 70% of the time. You can use the returned values as indexes into the array of ad codes. If you want the opposite to happen, e.g. the SECOND ad code to come up only 30% of the time, just invert the threshold: PHP Code: `$rand = rand_threshold(70);` For the 50/50 scenario you first outlined, it should be obvious what to do PHP Code: `$rand = rand_threshold(50);`

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