PHP help needed - again!

electricbeat · 07-08-2006, 12:12 PM

PHP Code:

  <?php

????: NamePros.com http://www.namepros.com/programming/214848-php-help-needed-again.html
????: NamePros.com http://www.namepros.com/showthread.php?t=214848
//the config file should connect to mysql.

require("config.php");

    

//select database

mysql_select_db("users");

 
$search = $_POST["search"];

//assigns the value of the entered search term in to the variable "search"

 
 
$result = mysql_query("SELECT * FROM users where username LIKE '%$search%'"); 

 
//note "username" would be the field the search looks up, so if you searched for "Waffles" it would look up waffles username in the table users.

 
while($r=mysql_fetch_array($result))

//grabs all the content it found

{    

  

//then change this to match your mysql columns..this will be the information displayed. You could just have username.

 
   $id=$r["id"];

   $username=$r["username"];

   $email=$r["email"];

   $location=$r["location"];

   $song1=$r["song1"];

   $song2=$r["song2"];

   $song3=$r["song3"];

   $song4=$r["song4"];

   $song5=$r["song5"];

   $song6=$r["song6"];

   $song7=$r["song7"];

   $song8=$r["song8"];

   $song9=$r["song9"];

   $song10=$r["song10"];

   $artist1=$r["artist1"];

   $artist2=$r["artist2"];

   $artist3=$r["artist3"];

   $artist4=$r["artist4"];

   $artist5=$r["artist5"];

   $artist6=$r["artist6"];

   $artist7=$r["artist7"];

   $artist8=$r["artist8"];

   $artist9=$r["artist9"];

   $artist10=$r["artist10"];

//and so on

   

   // then just display the row

   echo "Username: <i>$username</i><br />

Location: <i>$location</i><br />

Email: <i>$email</i><br><br>

 
<b>Music Interests</b><br />

1. $artist1 - <i>$song1</i><br />

2. $artist2 - <i>$song2</i><br />

3. $artist3 - <i>$song3</i><br />

4. $artist4 - <i>$song4</i><br />

5. $artist5 - <i>$song5</i><br />

6. $artist6 - <i>$song6</i><br />

7. $artist7 - <i>$song7</i><br />

8. $artist8 - <i>$song8</i><br />

9. $artist9 - <i>$song9</i><br />

10. $artist10 - <i>$song10</i><br />";

}

?>

So, I have a form that processes this file(search.php). If I type nothing in the form and push enter, I get all the results for all usernames. Instead I would prefer it to say ' You must enter text too search '. Also, when I search something that isn't in the database, and it's not found I don't have any error message. How could I make it so it returns ' No result found '.

All help appreciated.

hairyfreak · 07-08-2006, 01:12 PM

For the first part, after this:

PHP Code:

  $search = $_POST["search"];

//assigns the value of the entered search term in to the variable "search"

Put this:

PHP Code:

  if($search == NULL) {

     echo "The search field was left blank, please go back and try again.";

????: NamePros.com http://www.namepros.com/showthread.php?t=214848
}

Then for the next part, after this:

PHP Code:

  $result = mysql_query("SELECT * FROM users where username LIKE '%$search%'");

Place this:

PHP Code:

  if(!mysql_fetch_array($result)) {

     echo "No results found.";

}

I think they should both work, not tested them though.

electricbeat · 07-08-2006, 01:29 PM

thank you! The no results found part works

But, the thing where you enter no text doesnt

Flubber · 07-08-2006, 04:02 PM

Try changing that part to:

PHP Code:

  if(!$search) {

????: NamePros.com http://www.namepros.com/showthread.php?t=214848
     echo "The search field was left blank, please go back and try again.";

}

-PS- · 07-08-2006, 04:34 PM

Originally Posted by electricbeat

PHP Code:

  <?php

//the config file should connect to mysql.

require("config.php");

    

//select database

mysql_select_db("users");

 
$search = $_POST["search"];

//assigns the value of the entered search term in to the variable "search"

 
 
$result = mysql_query("SELECT * FROM users where username LIKE '%$search%'"); 

 
//note "username" would be the field the search looks up, so if you searched for "Waffles" it would look up waffles username in the table users.

 
while($r=mysql_fetch_array($result))

//grabs all the content it found

{    

  

//then change this to match your mysql columns..this will be the information displayed. You could just have username.

 
   $id=$r["id"];

   $username=$r["username"];

   $email=$r["email"];

   $location=$r["location"];

   $song1=$r["song1"];

   $song2=$r["song2"];

   $song3=$r["song3"];

   $song4=$r["song4"];

   $song5=$r["song5"];

   $song6=$r["song6"];

   $song7=$r["song7"];

   $song8=$r["song8"];

   $song9=$r["song9"];

   $song10=$r["song10"];

   $artist1=$r["artist1"];

????: NamePros.com http://www.namepros.com/showthread.php?t=214848
   $artist2=$r["artist2"];

   $artist3=$r["artist3"];

   $artist4=$r["artist4"];

   $artist5=$r["artist5"];

   $artist6=$r["artist6"];

   $artist7=$r["artist7"];

   $artist8=$r["artist8"];

   $artist9=$r["artist9"];

   $artist10=$r["artist10"];

//and so on

   

   // then just display the row

   echo "Username: <i>$username</i><br />

Location: <i>$location</i><br />

Email: <i>$email</i><br><br>

 
<b>Music Interests</b><br />

1. $artist1 - <i>$song1</i><br />

2. $artist2 - <i>$song2</i><br />

3. $artist3 - <i>$song3</i><br />

4. $artist4 - <i>$song4</i><br />

5. $artist5 - <i>$song5</i><br />

6. $artist6 - <i>$song6</i><br />

7. $artist7 - <i>$song7</i><br />

????: NamePros.com http://www.namepros.com/showthread.php?t=214848
8. $artist8 - <i>$song8</i><br />

9. $artist9 - <i>$song9</i><br />

10. $artist10 - <i>$song10</i><br />";

}

?>

So, I have a form that processes this file(search.php). If I type nothing in the form and push enter, I get all the results for all usernames. Instead I would prefer it to say ' You must enter text too search '. Also, when I search something that isn't in the database, and it's not found I don't have any error message. How could I make it so it returns ' No result found '.

All help appreciated.

PHP Code:

   if($search == NULL) {

     echo "The search field was left blank, please go back and try again.";

}

that will work - just move the } to just before the ?>

ALso, you could change it to

PHP Code:

  if(strlen($search)<3) {

to specifiy a minimum search lenght as well (just the if bit, and 3 would be the minimum lenght)

electricbeat · 07-09-2006, 01:47 AM

Thanks guys, it was sorted on another forum though, although I did use part of hairy's code, thanks

hairyfreak · 07-10-2006, 11:29 AM

No problem, glad to have helped

Scolls · 07-15-2006, 02:59 AM

"SELECT * FROM users where username LIKE '%$search%'" is a slow query, and searches through your entire table.

Why not rather have "SELECT * FROM users where username = '$search'" assuming the query is being built from the visitor's click on a username? Then also create an index on username for the first 2 or 3 characters?

Eric · 07-15-2006, 03:11 AM

If you hadn't noticed,

Quote:

electricbeat
Account Closed

Thread closed.

07-08-2006, 12:12 PM	THREAD STARTER #1 (permalink)
electricbeat Account Closed Join Date: Jul 2006 Posts: 81	PHP help needed - again! PHP Code: <?php ????: NamePros.com http://www.namepros.com/programming/214848-php-help-needed-again.html ????: NamePros.com http://www.namepros.com/showthread.php?t=214848 //the config file should connect to mysql. require("config.php"); //select database mysql_select_db("users"); $search = $_POST["search"]; //assigns the value of the entered search term in to the variable "search" $result = mysql_query("SELECT * FROM users where username LIKE '%$search%'"); //note "username" would be the field the search looks up, so if you searched for "Waffles" it would look up waffles username in the table users. while($r=mysql_fetch_array($result)) //grabs all the content it found { //then change this to match your mysql columns..this will be the information displayed. You could just have username. $id=$r["id"]; $username=$r["username"]; $email=$r["email"]; $location=$r["location"]; $song1=$r["song1"]; $song2=$r["song2"]; $song3=$r["song3"]; $song4=$r["song4"]; $song5=$r["song5"]; $song6=$r["song6"]; $song7=$r["song7"]; $song8=$r["song8"]; $song9=$r["song9"]; $song10=$r["song10"]; $artist1=$r["artist1"]; $artist2=$r["artist2"]; $artist3=$r["artist3"]; $artist4=$r["artist4"]; $artist5=$r["artist5"]; $artist6=$r["artist6"]; $artist7=$r["artist7"]; $artist8=$r["artist8"]; $artist9=$r["artist9"]; $artist10=$r["artist10"]; //and so on // then just display the row echo "Username: <i>$username</i><br /> Location: <i>$location</i><br /> Email: <i>$email</i><br><br> <b>Music Interests</b><br /> 1. $artist1 - <i>$song1</i><br /> 2. $artist2 - <i>$song2</i><br /> 3. $artist3 - <i>$song3</i><br /> 4. $artist4 - <i>$song4</i><br /> 5. $artist5 - <i>$song5</i><br /> 6. $artist6 - <i>$song6</i><br /> 7. $artist7 - <i>$song7</i><br /> 8. $artist8 - <i>$song8</i><br /> 9. $artist9 - <i>$song9</i><br /> 10. $artist10 - <i>$song10</i><br />"; } ?> So, I have a form that processes this file(search.php). If I type nothing in the form and push enter, I get all the results for all usernames. Instead I would prefer it to say ' You must enter text too search '. Also, when I search something that isn't in the database, and it's not found I don't have any error message. How could I make it so it returns ' No result found '. All help appreciated.

07-08-2006, 01:12 PM	#2 (permalink)
hairyfreak NamePros Regular Join Date: Dec 2005 Location: Derbyshire, UK Posts: 887	For the first part, after this: PHP Code: `$search = $_POST["search"]; //assigns the value of the entered search term in to the variable "search"` Put this: PHP Code: `if($search == NULL) { echo "The search field was left blank, please go back and try again."; ????: NamePros.com http://www.namepros.com/showthread.php?t=214848 }` Then for the next part, after this: PHP Code: `$result = mysql_query("SELECT * FROM users where username LIKE '%$search%'");` Place this: PHP Code: `if(!mysql_fetch_array($result)) { echo "No results found."; }` I think they should both work, not tested them though.

07-08-2006, 04:02 PM	#4 (permalink)
Flubber NamePros Regular Join Date: Jun 2005 Location: UK Posts: 688	Try changing that part to: PHP Code: `if(!$search) { ????: NamePros.com http://www.namepros.com/showthread.php?t=214848 echo "The search field was left blank, please go back and try again."; }`

07-08-2006, 01:29 PM	THREAD STARTER #3 (permalink)
electricbeat Account Closed Join Date: Jul 2006 Posts: 81	thank you! The no results found part works But, the thing where you enter no text doesnt

07-09-2006, 01:47 AM	THREAD STARTER #6 (permalink)
electricbeat Account Closed Join Date: Jul 2006 Posts: 81	Thanks guys, it was sorted on another forum though, although I did use part of hairy's code, thanks

07-10-2006, 11:29 AM	#7 (permalink)
hairyfreak NamePros Regular Join Date: Dec 2005 Location: Derbyshire, UK Posts: 887	No problem, glad to have helped

07-15-2006, 02:59 AM	#8 (permalink)
Scolls New Member Join Date: Jul 2006 Posts: 20	"SELECT * FROM users where username LIKE '%$search%'" is a slow query, and searches through your entire table. Why not rather have "SELECT * FROM users where username = '$search'" assuming the query is being built from the visitor's click on a username? Then also create an index on username for the first 2 or 3 characters?

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