PHP Parse Error... do you see it?

Jeanco · 12-31-2003, 11:00 AM

I'm getting a parse error on line 20 - if ($x % 4 = 0) {

For those who don't know, % is for modulus division (remainder division). Anyone see why I'm getting a parse error?

PHP Code:

 
<table width="562" border="0" cellspacing="0" cellpadding="0">

  <tr>

    <td width=220 align="left" bgcolor="#FFFFFF">

    pic

    </td>

    <td width=342 align="left" bgcolor="#FFFFFF">

    

    <table width="342" border="0" cellspacing="0" cellpadding="0">

      <tr>

    <?php

        /* VARIABLES:

        $num_pics = number of pictures in teh folder

        $x = a counter

        $file_base = filename without the 3-digit number extension */

        $num_pics = 71;

        $file_base = "images/Whitby/Hockey/Atom AAA/2003-2004/thumbnails/atomaaa";        

        $x = 1;

        

        if ($num_pics >= $x) {

            if ($x % 4 = 0) {

                echo "<td width=75><img src='" . $file_base . leading_zero($x, 3, 0) . ".jpg' alt='Thumbnails' border=0></td>" . "<td width=15>&nbsp;</td></tr><tr>"; //print with new row

                $x++; //increase pic #

            }

            else {

                echo "<td width=75><img src='" . $file_base . leading_zero($x, 3, 0) . ".jpg' alt='Thumbnails' border=0></td>" . "<td width=15>&nbsp;</td>"; //print without new row

                $x++;

            }

        else {

            $x--; //x is now one greater than the number of files, so bump it down

            $y = 4 - ($x % 4); //find the number of empty rows that need filling

            

            while ($y > 0 ) {

                echo "<td width=75>&nbsp;</td><td width=15>&nbsp;</td>";

                $y--;

????: NamePros.com http://www.namepros.com/programming/16186-php-parse-error-do-you-see.html
            }

        }

    ?>

????: NamePros.com http://www.namepros.com/showthread.php?t=16186
      </tr>

    </table>

 
    

    </td>

  </tr>

</table>

<?php

function leading_zero( $aNumber, $intPart, $floatPart=NULL, $dec_point=NULL, $thousands_sep=NULL) {        //Note: The $thousands_sep has no real function because it will be "disturbed" by plain leading zeros -> the main goal of the function

  $formattedNumber = $aNumber;

  if (!is_null($floatPart)) {    //without 3rd parameters the "float part" of the float shouldn't be touched

   $formattedNumber = number_format($formattedNumber, $floatPart, $dec_point, $thousands_sep);

   }

  //if ($intPart > floor(log10($formattedNumber)))

   $formattedNumber = str_repeat("0",($intPart + -1 - floor(log10($formattedNumber)))).$formattedNumber;

  return $formattedNumber;

  }

  ?>

deadserious · 12-31-2003, 11:18 AM

I think there's a few errors in there.

You should have two equals signs there since you're comparing/evaluating rather than assigning.

if ($x % 4 == 0)

I'm not sure if that's why you're getting errors though. But I also noticed you have two else statements in a row. I think you need to change the last one to elseif or if.

You're also missing some quotes and the semi-colon at the top where you declared your variables.

Jeanco · 12-31-2003, 11:33 AM

Yup, thanks for catching the == error.

I don't see anything wrong with how I declared variables at the top. The string has quotes and semicolon and the int variables have a semi colon.

How do nested if statements work in PHP? I come from a VB background and am used to use the

if x = 1
do something
elseif
do something
else
do soemthing
end if

Does php have an end if line of code? If not then how do you nest if statements?

RJ · 12-31-2003, 12:33 PM

Hi Ryan,

The format for php comparisons with elses:

if ($x ==1) {
>>do something<<
}
elseif ($x==2) {
>> do something else <<
}
else {
>> do this <<
}

You need to use a comparison with your elseif statement and you can't have two else statements on the same 'if'.

Jeanco · 12-31-2003, 12:36 PM

Thanks RJ but thats not what I'm after.

The first else statement was for the nested 'if' (the second if) and the other else statement was for the first 'if'. In VB this would've worked:
????: NamePros.com http://www.namepros.com/showthread.php?t=16186

Code:

if x = whatever
    if y = whatever
       do this
    else
       do this
    end if
else
    do this
end if

I've got the code figured out from WHT members but am still wondering if I am able to nest if statements like this in PHP

RJ · 12-31-2003, 12:42 PM

Yes, you can nest statements like that no problem.

I think I misread your code initially because it was missing a closing bracket for one of your 'if' statements, it appeared as if there were two else statements on the same if. I see what you're trying to do now.

PHP Code:

 
<table width="562" border="0" cellspacing="0" cellpadding="0">

  <tr>

    <td width=220 align="left" bgcolor="#FFFFFF">

    pic

    </td>

    <td width=342 align="left" bgcolor="#FFFFFF">

    

    <table width="342" border="0" cellspacing="0" cellpadding="0">

      <tr>

    <?php

        /* VARIABLES:

        $num_pics = number of pictures in teh folder

        $x = a counter

        $file_base = filename without the 3-digit number extension */

        $num_pics = 71;

        $file_base = "images/Whitby/Hockey/Atom AAA/2003-2004/thumbnails/atomaaa";        

        $x = 1;

        

        if ($num_pics >= $x) {

            if ($x%4 == 0) {

                echo "<td width=75><img src=\"".$file_base.leading_zero($x, 3, 0).".jpg\" alt=\"Thumbnails\" border=0></td><td width=15>&nbsp;</td></tr><tr>"; //print with new row

                $x++; //increase pic #

                                    } 

            else {

                echo "<td width=75><img src=\"".$file_base.leading_zero($x, 3, 0).".jpg\" alt=\"Thumbnails\" border=0></td><td width=15>&nbsp;</td>"; 

                    //print without new row

                    $x++;

                     } 

        }

            else {

                   $x--; //x is now one greater than the number of files, so bump it down

                   $y = 4 - ($x % 4); //find the number of empty rows that need filling

                    while ($y > 0 ) { echo "<td width=75>&nbsp;</td><td width=15>&nbsp;</td>";  $y--;    }

                    }

 
 
    ?>

      </tr>

    </table>

 
    

    </td>

  </tr>

</table>

<?php

function leading_zero( $aNumber, $intPart, $floatPart=NULL, $dec_point=NULL, $thousands_sep=NULL) {        //Note: The $thousands_sep has no real function because it will be "disturbed" by plain leading zeros -> the main goal of the function

????: NamePros.com http://www.namepros.com/showthread.php?t=16186
  $formattedNumber = $aNumber;

  if (!is_null($floatPart)) {    //without 3rd parameters the "float part" of the float shouldn't be touched

   $formattedNumber = number_format($formattedNumber, $floatPart, $dec_point, $thousands_sep);

   }

  //if ($intPart > floor(log10($formattedNumber)))

   $formattedNumber = str_repeat("0",($intPart + -1 - floor(log10($formattedNumber)))).$formattedNumber;

????: NamePros.com http://www.namepros.com/showthread.php?t=16186
  return $formattedNumber;

  }

  ?>

Jeanco · 12-31-2003, 12:49 PM

Ah I see... just need another }

Thanks

deadserious · 12-31-2003, 02:16 PM

Quote:

Originally posted by Jeanco
Yup, thanks for catching the == error.

I don't see anything wrong with how I declared variables at the top. The string has quotes and semicolon and the int variables have a semi colon.

Oops! LOL I just took a quick look at it and I was looking where you have the multi line comments up at the top. That's why I thought you were missing some quotes and such.

And I also thought there was only one if statement which is why I was confused with both your else statements in a row like that. But I see them now.

RJ · 12-31-2003, 02:33 PM

It's always a challenge debugging other programmer's scripts until you learn their programming styles. Programming languages like Perl and PHP allow multiple ways to accomplish the same task.

12-31-2003, 11:00 AM	THREAD STARTER #1 (permalink)
Jeanco RyanPrice.ca - Developer Join Date: Dec 2003 Posts: 1,328	PHP Parse Error... do you see it? I'm getting a parse error on line 20 - if ($x % 4 = 0) { For those who don't know, % is for modulus division (remainder division). Anyone see why I'm getting a parse error? PHP Code: <table width="562" border="0" cellspacing="0" cellpadding="0"> <tr> <td width=220 align="left" bgcolor="#FFFFFF"> pic </td> <td width=342 align="left" bgcolor="#FFFFFF"> <table width="342" border="0" cellspacing="0" cellpadding="0"> <tr> <?php /* VARIABLES: $num_pics = number of pictures in teh folder $x = a counter $file_base = filename without the 3-digit number extension */ $num_pics = 71; $file_base = "images/Whitby/Hockey/Atom AAA/2003-2004/thumbnails/atomaaa"; $x = 1; if ($num_pics >= $x) { if ($x % 4 = 0) { echo "<td width=75><img src='" . $file_base . leading_zero($x, 3, 0) . ".jpg' alt='Thumbnails' border=0></td>" . "<td width=15> </td></tr><tr>"; //print with new row $x++; //increase pic # } else { echo "<td width=75><img src='" . $file_base . leading_zero($x, 3, 0) . ".jpg' alt='Thumbnails' border=0></td>" . "<td width=15> </td>"; //print without new row $x++; } else { $x--; //x is now one greater than the number of files, so bump it down $y = 4 - ($x % 4); //find the number of empty rows that need filling while ($y > 0 ) { echo "<td width=75> </td><td width=15> </td>"; $y--; ????: NamePros.com http://www.namepros.com/programming/16186-php-parse-error-do-you-see.html } } ?> ????: NamePros.com http://www.namepros.com/showthread.php?t=16186 </tr> </table> </td> </tr> </table> <?php function leading_zero( $aNumber, $intPart, $floatPart=NULL, $dec_point=NULL, $thousands_sep=NULL) { //Note: The $thousands_sep has no real function because it will be "disturbed" by plain leading zeros -> the main goal of the function $formattedNumber = $aNumber; if (!is_null($floatPart)) { //without 3rd parameters the "float part" of the float shouldn't be touched $formattedNumber = number_format($formattedNumber, $floatPart, $dec_point, $thousands_sep); } //if ($intPart > floor(log10($formattedNumber))) $formattedNumber = str_repeat("0",($intPart + -1 - floor(log10($formattedNumber)))).$formattedNumber; return $formattedNumber; } ?> __________________ Ryan Price - Webmaster www.HostDurham.com - For Hosting \| www.jeanco.ca - For Webdesign

12-31-2003, 11:33 AM	THREAD STARTER #3 (permalink)
Jeanco RyanPrice.ca - Developer Join Date: Dec 2003 Posts: 1,328	Yup, thanks for catching the == error. I don't see anything wrong with how I declared variables at the top. The string has quotes and semicolon and the int variables have a semi colon. How do nested if statements work in PHP? I come from a VB background and am used to use the if x = 1 do something elseif do something else do soemthing end if Does php have an end if line of code? If not then how do you nest if statements? __________________ Ryan Price - Webmaster www.HostDurham.com - For Hosting \| www.jeanco.ca - For Webdesign

12-31-2003, 12:33 PM	#4 (permalink)
RJ NamePros Webmaster Join Date: Feb 2003 Posts: 12,930 Follow @DomainBuyer	Hi Ryan, The format for php comparisons with elses: if ($x ==1) { >>do something<< } elseif ($x==2) { >> do something else << } else { >> do this << } You need to use a comparison with your elseif statement and you can't have two else statements on the same 'if'. __________________ @DomainBuyer facebook

12-31-2003, 12:36 PM	THREAD STARTER #5 (permalink)
Jeanco RyanPrice.ca - Developer Join Date: Dec 2003 Posts: 1,328	Thanks RJ but thats not what I'm after. The first else statement was for the nested 'if' (the second if) and the other else statement was for the first 'if'. In VB this would've worked: ????: NamePros.com http://www.namepros.com/showthread.php?t=16186 Code: if x = whatever if y = whatever do this else do this end if else do this end if I've got the code figured out from WHT members but am still wondering if I am able to nest if statements like this in PHP __________________ Ryan Price - Webmaster www.HostDurham.com - For Hosting \| www.jeanco.ca - For Webdesign

12-31-2003, 12:42 PM	#6 (permalink)
RJ NamePros Webmaster Join Date: Feb 2003 Posts: 12,930 Follow @DomainBuyer	Yes, you can nest statements like that no problem. I think I misread your code initially because it was missing a closing bracket for one of your 'if' statements, it appeared as if there were two else statements on the same if. I see what you're trying to do now. PHP Code: <table width="562" border="0" cellspacing="0" cellpadding="0"> <tr> <td width=220 align="left" bgcolor="#FFFFFF"> pic </td> <td width=342 align="left" bgcolor="#FFFFFF"> <table width="342" border="0" cellspacing="0" cellpadding="0"> <tr> <?php /* VARIABLES: $num_pics = number of pictures in teh folder $x = a counter $file_base = filename without the 3-digit number extension / $num_pics = 71; $file_base = "images/Whitby/Hockey/Atom AAA/2003-2004/thumbnails/atomaaa"; $x = 1; if ($num_pics >= $x) { if ($x%4 == 0) { echo "<td width=75><img src=\"".$file_base.leading_zero($x, 3, 0).".jpg\" alt=\"Thumbnails\" border=0></td><td width=15> </td></tr><tr>"; //print with new row $x++; //increase pic # } else { echo "<td width=75><img src=\"".$file_base.leading_zero($x, 3, 0).".jpg\" alt=\"Thumbnails\" border=0></td><td width=15> </td>"; //print without new row $x++; } } else { $x--; //x is now one greater than the number of files, so bump it down $y = 4 - ($x % 4); //find the number of empty rows that need filling while ($y > 0 ) { echo "<td width=75> </td><td width=15> </td>"; $y--; } } ?> </tr> </table> </td> </tr> </table> <?php function leading_zero( $aNumber, $intPart, $floatPart=NULL, $dec_point=NULL, $thousands_sep=NULL) { //Note: The $thousands_sep has no real function because it will be "disturbed" by plain leading zeros -> the main goal of the function ????: NamePros.com http://www.namepros.com/showthread.php?t=16186 $formattedNumber = $aNumber; if (!is_null($floatPart)) { //without 3rd parameters the "float part" of the float shouldn't be touched $formattedNumber = number_format($formattedNumber, $floatPart, $dec_point, $thousands_sep); } //if ($intPart > floor(log10($formattedNumber))) $formattedNumber = str_repeat("0",($intPart + -1 - floor(log10($formattedNumber)))).$formattedNumber; ????: NamePros.com http://www.namepros.com/showthread.php?t=16186 return $formattedNumber; } ?> __________________ @DomainBuyer facebook Last edited by -RJ-; 12-31-2003 at 12:47 PM.*

12-31-2003, 11:18 AM	#2 (permalink)
deadserious Senior Member Join Date: Aug 2002 Posts: 1,255	I think there's a few errors in there. You should have two equals signs there since you're comparing/evaluating rather than assigning. if ($x % 4 == 0) I'm not sure if that's why you're getting errors though. But I also noticed you have two else statements in a row. I think you need to change the last one to elseif or if. You're also missing some quotes and the semi-colon at the top where you declared your variables.

12-31-2003, 12:49 PM	THREAD STARTER #7 (permalink)
Jeanco RyanPrice.ca - Developer Join Date: Dec 2003 Posts: 1,328	Ah I see... just need another } Thanks __________________ Ryan Price - Webmaster www.HostDurham.com - For Hosting \| www.jeanco.ca - For Webdesign

12-31-2003, 02:33 PM	#9 (permalink)
RJ NamePros Webmaster Join Date: Feb 2003 Posts: 12,930 Follow @DomainBuyer	It's always a challenge debugging other programmer's scripts until you learn their programming styles. Programming languages like Perl and PHP allow multiple ways to accomplish the same task. __________________ @DomainBuyer facebook

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