successgold

Hi,
????: NamePros.com http://www.namepros.com/programming/15277-javascript-popup-problem.html

I have a popup on my website which appears every time someone leaves my homepage. Unfortunately,howver, it appears even if someone visits another page on my site. Please can someone tell me how to change this so that it only appears when people leave the site altogether?

My current code is below.

Thank you.
Joe Beaven




<SCRIPT LANGUAGE='JAVASCRIPT' TYPE='TEXT/JAVASCRIPT'>
<!--
var win=null;
function NewWindow(mypage,myname,w,h,pos,infocus){
if(GetCookie("sid") == "999"){return;}
document.cookie="sid=999; Path=/; Expires= " + getFuture(1);
if(pos=="random"){myleft=(screen.width)?Math.floor (Math.random()*(screen.width-w)):100;mytop=(screen.height)?Math.floor(Math.rand om()*((screen.height-h)-75)):100;}
if(pos=="center"){myleft=(screen.width)?(screen.wi dth-w)/2:100;mytop=(screen.height)?(screen.height-h)/2:100;}
else if((pos!='center' && pos!="random") || pos==null){myleft=0;mytop=20}
settings="width=" + w + ",height=" + h + ",top=" + mytop + ",left=" + myleft + " ,scrollbars=yes,location=no,directories=no,status=
no,menubar=no,toolbar=no,resizable=no";win=window. open(mypage,myname,settings);
win.focus();}

function getFuture(f){
var d = new Date();
d.setTime(d.getTime() + (86400000 * f));
return d;
}

function GetCookie (name) {
var arg = name + "=";
var alen = arg.length;
var clen = document.cookie.length;
var i = 0;
while (i < clen) {
var j = i + alen;
if (document.cookie.substring(i, j) == arg)
return getCookieVal (j);
i = document.cookie.indexOf(" ", i) + 1;
if (i == 0) break;
}
return null;
}

function getCookieVal (offset) {
var endstr = document.cookie.indexOf (";", offset);
if (endstr == -1)
endstr = document.cookie.length;
return unescape(document.cookie.substring(offset, endstr));
}
// -->
</script>

deadserious

This script may work for what you're wanting to do http://javascriptkit.com/script/script2/popunder.shtml