Explain this please

unknowngiver · 07-28-2005, 07:10 AM

Code:

<?php
$line = date("m.d.y") . "|" . $HTTP_POST_VARS['name'];
$line .= "|" . $HTTP_POST_VARS['news'];
$line = str_replace("\r\n","<BR>",$line);
$line .= "\r\n";
?>

Okay, I am reading a tutorial and i really dont get this part and they didnt explain it either
????: NamePros.com http://www.namepros.com/programming/110631-explain-this-please.html

y is there 4 $line variables? i thought u could only have one
and y is there a "." before the "="

and whats "/r/n" etc...

luxinterior · 07-28-2005, 07:23 AM

The . is appending the second part of the string to the first (which is happening twice in your example). And /r/n means line feed and carriage return (basically a new line). In this example it's replacing the line feed characters with the html equivolent '<br>'.

Lux

unknowngiver · 07-28-2005, 07:27 AM

still dont get it
can u explain the whole code..from start to the end and wt it means {wt its suppose to do}

eagle12 · 07-28-2005, 09:28 AM

PHP Code:

  
<?php

//This line is appending the date with a user entered named

//i.e.: 07.28.2005|Kris

????: NamePros.com http://www.namepros.com/showthread.php?t=110631
$line = date("m.d.y") . "|" . $HTTP_POST_VARS['name'];

//This line appends the previous line with the user entered news

//the line now looks like this: 

//07.28.2005|Kris|news the user entered.

//This is another line the user entered for the news.

$line .= "|" . $HTTP_POST_VARS['news'];

//This line checks to see if the user pressed enter, and replaces it with <br>

//The line now looks like this:

//07.28.2005|Kris|news the user entered.<br>This is another line the user entered for the news.

$line = str_replace("\r\n","<BR>",$line);

/*This last line adds a new line character to the end of the string so that it is easier to read. Moves it down the next line in the source, but not on the page.*/

$line .= "\r\n";

?>

Hope this helps.

unknowngiver · 07-28-2005, 10:43 AM

okay great

thanks

unknowngiver · 07-29-2005, 06:24 PM

okay i read it again and again
but i stil dont get this part

$line = str_replace("\r\n","<BR>",$line);

wt is \r\n ?
thts the code to see if someone pressed ENTER?

luxinterior · 07-29-2005, 06:32 PM

The str_replace is a function. It replaces the first part with the second part found in the third part so...

str_replace(find_this, replace_with_this, in_this).

You might want to take a look at www.php.net and find some basic tutorials on Google.

BTW I think eagle12 went above and beyond the call of duty with his explanation. I hope he gets some rep points for it

Good luck

Lux

harkster · 07-29-2005, 07:03 PM

Spiffy little snippit.

The \r\n -- in linux the \ is an escape character that says there is something special about the next character.

The \r = carriage return (cr). on most systems it tlaces the cursor at the beginning of the current line but on some systems it is a cr + lf and can be frustrating when trying to build a mime email.

The \n is a new line (lf). The crusor is placed on the next line at the end of the previous line.

Together they place the cursor at the far left of the next line.

I am not an expert but got this pounded in while writing my FormMail script.

unknowngiver · 07-29-2005, 07:22 PM

Thanks guyz
rep added

here is a lil bit of more code tht i need help with :$

Code:

foreach($data as $element) {
    $element = trim($element);
    $pieces = explode("|", $element);
    echo $pieces[2] . "<BR>" . "<b>Posted by " . $pieces[1] . " on " . $pieces[0] . "</b><BR><BR>";
}

k i THINK tht
????: NamePros.com http://www.namepros.com/showthread.php?t=110631
foreach($data as $element)
converts all the stuff from $data to $element? am i right

harkster · 07-29-2005, 10:32 PM

Originally Posted by unknowngiver

Thanks guyz
rep added

here is a lil bit of more code tht i need help with :$

Code:

foreach($data as $element) {
    $element = trim($element);
    $pieces = explode("|", $element);
    echo $pieces[2] . "<BR>" . "<b>Posted by " . $pieces[1] . " on " . $pieces[0] . "</b><BR><BR>";
}

k i THINK tht
????: NamePros.com http://www.namepros.com/showthread.php?t=110631
foreach($data as $element)
converts all the stuff from $data to $element? am i right

I hope this is right.
Data is an array of elements ($elements) where each element is a string like xxx|yyy|zzz. Foreach will loop through all elements.
$element = trim($element); // strip any leading or trailing blanks
$pieces = explode("|", $element); //Break the string $element into pieces defined by | and create an array of $pieces.
the echo prints the pieces in the desired order for each element of $data. In this case zzz Posted by yyy on xxx

Help??

unknowngiver · 07-31-2005, 11:46 AM

yup tht makes sense

thanks

unknowngiver · 08-02-2005, 11:16 AM

okay a little help now

$password='zubair'
if($HTTP_POST_VARS['submit']) {
if($HTTP_POST_VARS['password'] == '$password') {

here is the code
now what i want is tht the script should check if the password is what i defined in "$password" .... but it gives me this error

Parse error: parse error, unexpected T_IF in /home/zubair/public_html/news/addnews.php on line 13

mholt · 08-02-2005, 12:37 PM

You want to make sure that $HTTP_POST_VARS['password'] is equal to $password?

Here:

Code:

if (isset($HTTP_POST_VARS['submit]))
{
if ($HTTP_POST_VARS['password'] != $password) {
echo('The passwords do not match.');
}
}

That what you mean?

unknowngiver · 08-02-2005, 08:25 PM

Dont think so
????: NamePros.com http://www.namepros.com/showthread.php?t=110631
here is the full code

Code:

$password='zubair'
if($HTTP_POST_VARS['submit']) {
    if($HTTP_POST_VARS['password'] == '$password') {
        if(!$HTTP_POST_VARS['name']) {
            echo "You must enter a name";
            exit;
        }
        if(!$HTTP_POST_VARS['news']) {
            echo "You must enter some news";
            exit;
        }
        if(strstr($HTTP_POST_VARS['name'],"|")) {
            echo "Name cannot contain the pipe symbol - |";
            exit;
        }
        if(strstr($HTTP_POST_VARS['news'],"|")) {
            echo "News cannot contain the pipe symbol - |";
            exit;
        }
        $fp = fopen('news.txt','a');
        if(!$fp) {
            echo "Error opening file!";
            exit;
        }
        $line = date("m.d.y") . "|" . $HTTP_POST_VARS['name'];
        $line .= "|" . $HTTP_POST_VARS['news'];
        $line = str_replace("\r\n","<BR>",$line);
        $line .= "\r\n";
        fwrite($fp, $line);
        if(!fclose($fp)) {
            echo "Error closing file!";
            exit;
        }
    } else {
        echo "Bad Password";
    }
}

?>

luxinterior · 08-02-2005, 08:31 PM

Your've got the variable $password in single quotation marks making it a string literal as in no longer a variable but the string $password. Remove them and it should be ok.

Lux

unknowngiver · 08-03-2005, 10:31 AM

Still the same
here is the code now

Code:

$password='zubair'
if($HTTP_POST_VARS['submit']) {
    if($HTTP_POST_VARS['password'] == $password) {
        if(!$HTTP_POST_VARS['name']) {
            echo "You must enter a name";
            exit;
        }
        if(!$HTTP_POST_VARS['news']) {
            echo "You must enter some news";
            exit;
        }

unknowngiver · 08-05-2005, 09:23 AM

anyone wana give it a try please

mholt · 08-05-2005, 11:24 AM

You have to close two more curly brackets at the end.

Amnezia · 08-05-2005, 11:45 AM

you missing a semi colon at the end of the first line

mholt · 08-05-2005, 12:14 PM

Yes!!! Amnezia wins the prize! ^_^ (Lol my post was just a test to see if it'd distract you

)

Eric · 08-05-2005, 12:51 PM

Originally Posted by unknowngiver

Still the same
here is the code now

Code:

$password='zubair'
if($HTTP_POST_VARS['submit']) {
    if($HTTP_POST_VARS['password'] == $password) {
        if(!$HTTP_POST_VARS['name']) {
            echo "You must enter a name";
            exit;
        }
        if(!$HTTP_POST_VARS['news']) {
            echo "You must enter some news";
            exit;
        }

PHP Code:

  $password='zubair';

if($HTTP_POST_VARS['submit']) {

    if($HTTP_POST_VARS['password'] == $password) {

        if(!$HTTP_POST_VARS['name']) {

            echo "You must enter a name";

            exit();

        }

        if(!$HTTP_POST_VARS['news']) {

????: NamePros.com http://www.namepros.com/showthread.php?t=110631
            echo "You must enter some news";

            exit();

        }

}

Refrozen · 08-05-2005, 10:11 PM

. means append
\r\n means Winodws newline

unknowngiver · 08-07-2005, 09:34 PM

didnt work guys

Eric · 08-07-2005, 10:10 PM

nvmd

Just changed a couple of things.. Modified from my original post.

PHP Code:

  <?php

$password = 'zubair';

if($HTTP_POST_VARS['submit']) {

    if($HTTP_POST_VARS['password'] == $password) {

        if(!$HTTP_POST_VARS['name']) {

            echo "You must enter a name";

            exit;

        }

        if(!$HTTP_POST_VARS['news']) {

            echo "You must enter some news";

            exit;

        }

}

?>

07-28-2005, 07:10 AM	THREAD STARTER #1 (permalink)
unknowngiver Senior Member Join Date: May 2005 Location: Ontario Canada Posts: 3,088	Explain this please Code: <?php $line = date("m.d.y") . "\|" . $HTTP_POST_VARS['name']; $line .= "\|" . $HTTP_POST_VARS['news']; $line = str_replace("\r\n","<BR>",$line); $line .= "\r\n"; ?> Okay, I am reading a tutorial and i really dont get this part and they didnt explain it either ????: NamePros.com http://www.namepros.com/programming/110631-explain-this-please.html y is there 4 $line variables? i thought u could only have one and y is there a "." before the "=" and whats "/r/n" etc... __________________ Simplifying Engineering \|\| $$ Currency Converter $$ Julsh - Community/Dating Website \|\| Free Image hosting Fresh Proxies \|\| Random Proxy \|\| Troll Board

07-28-2005, 07:23 AM	#2 (permalink)
luxinterior Senior Member Join Date: Jul 2004 Location: Kizmiaz Posts: 1,091	The . is appending the second part of the string to the first (which is happening twice in your example). And /r/n means line feed and carriage return (basically a new line). In this example it's replacing the line feed characters with the html equivolent '<br>'. Lux __________________ 1 Cent Web Hosting @ Online HostGatorVoucher.com Adsense Hack for Vbulletin - Fully 3.6 Compatible ForexArea.com Free E-Course in Programming EA's

07-28-2005, 07:27 AM	THREAD STARTER #3 (permalink)
unknowngiver Senior Member Join Date: May 2005 Location: Ontario Canada Posts: 3,088	still dont get it can u explain the whole code..from start to the end and wt it means {wt its suppose to do} __________________ Simplifying Engineering \|\| $$ Currency Converter $$ Julsh - Community/Dating Website \|\| Free Image hosting Fresh Proxies \|\| Random Proxy \|\| Troll Board

07-28-2005, 09:28 AM	#4 (permalink)
eagle12 NamePros Member Join Date: Nov 2003 Location: Ontario, Canada Posts: 127	PHP Code: <?php //This line is appending the date with a user entered named //i.e.: 07.28.2005\|Kris ????: NamePros.com http://www.namepros.com/showthread.php?t=110631 $line = date("m.d.y") . "\|" . $HTTP_POST_VARS['name']; //This line appends the previous line with the user entered news //the line now looks like this: //07.28.2005\|Kris\|news the user entered. //This is another line the user entered for the news. $line .= "\|" . $HTTP_POST_VARS['news']; //This line checks to see if the user pressed enter, and replaces it with <br> //The line now looks like this: //07.28.2005\|Kris\|news the user entered.<br>This is another line the user entered for the news. $line = str_replace("\r\n","<BR>",$line); /This last line adds a new line character to the end of the string so that it is easier to read. Moves it down the next line in the source, but not on the page./ $line .= "\r\n"; ?> Hope this helps.

07-28-2005, 10:43 AM	THREAD STARTER #5 (permalink)
unknowngiver Senior Member Join Date: May 2005 Location: Ontario Canada Posts: 3,088	okay great thanks __________________ Simplifying Engineering \|\| $$ Currency Converter $$ Julsh - Community/Dating Website \|\| Free Image hosting Fresh Proxies \|\| Random Proxy \|\| Troll Board

07-29-2005, 06:24 PM	THREAD STARTER #6 (permalink)
unknowngiver Senior Member Join Date: May 2005 Location: Ontario Canada Posts: 3,088	okay i read it again and again but i stil dont get this part $line = str_replace("\r\n","<BR>",$line); wt is \r\n ? thts the code to see if someone pressed ENTER? __________________ Simplifying Engineering \|\| $$ Currency Converter $$ Julsh - Community/Dating Website \|\| Free Image hosting Fresh Proxies \|\| Random Proxy \|\| Troll Board

07-29-2005, 06:32 PM	#7 (permalink)
luxinterior Senior Member Join Date: Jul 2004 Location: Kizmiaz Posts: 1,091	The str_replace is a function. It replaces the first part with the second part found in the third part so... str_replace(find_this, replace_with_this, in_this). You might want to take a look at www.php.net and find some basic tutorials on Google. BTW I think eagle12 went above and beyond the call of duty with his explanation. I hope he gets some rep points for it Good luck Lux __________________ 1 Cent Web Hosting @ Online HostGatorVoucher.com Adsense Hack for Vbulletin - Fully 3.6 Compatible ForexArea.com Free E-Course in Programming EA's

07-29-2005, 07:03 PM	#8 (permalink)
harkster Senior Member Join Date: Mar 2004 Location: Red State Posts: 1,605	Spiffy little snippit. The \r\n -- in linux the \ is an escape character that says there is something special about the next character. The \r = carriage return (cr). on most systems it tlaces the cursor at the beginning of the current line but on some systems it is a cr + lf and can be frustrating when trying to build a mime email. The \n is a new line (lf). The crusor is placed on the next line at the end of the previous line. Together they place the cursor at the far left of the next line. I am not an expert but got this pounded in while writing my FormMail script. __________________ -- A Sometimes Light Hearted Journey Through The History of Shoes -- -- QUHL.com --

07-29-2005, 07:22 PM	THREAD STARTER #9 (permalink)
unknowngiver Senior Member Join Date: May 2005 Location: Ontario Canada Posts: 3,088	Thanks guyz rep added here is a lil bit of more code tht i need help with :$ Code: foreach($data as $element) { $element = trim($element); $pieces = explode("\|", $element); echo $pieces[2] . "<BR>" . "<b>Posted by " . $pieces[1] . " on " . $pieces[0] . "</b><BR><BR>"; } k i THINK tht ????: NamePros.com http://www.namepros.com/showthread.php?t=110631 foreach($data as $element) converts all the stuff from $data to $element? am i right __________________ Simplifying Engineering \|\| $$ Currency Converter $$ Julsh - Community/Dating Website \|\| Free Image hosting Fresh Proxies \|\| Random Proxy \|\| Troll Board

07-31-2005, 11:46 AM	THREAD STARTER #11 (permalink)
unknowngiver Senior Member Join Date: May 2005 Location: Ontario Canada Posts: 3,088	yup tht makes sense thanks __________________ Simplifying Engineering \|\| $$ Currency Converter $$ Julsh - Community/Dating Website \|\| Free Image hosting Fresh Proxies \|\| Random Proxy \|\| Troll Board

08-02-2005, 11:16 AM	THREAD STARTER #12 (permalink)
unknowngiver Senior Member Join Date: May 2005 Location: Ontario Canada Posts: 3,088	okay a little help now $password='zubair' if($HTTP_POST_VARS['submit']) { if($HTTP_POST_VARS['password'] == '$password') { here is the code now what i want is tht the script should check if the password is what i defined in "$password" .... but it gives me this error Parse error: parse error, unexpected T_IF in /home/zubair/public_html/news/addnews.php on line 13 __________________ Simplifying Engineering \|\| $$ Currency Converter $$ Julsh - Community/Dating Website \|\| Free Image hosting Fresh Proxies \|\| Random Proxy \|\| Troll Board

08-02-2005, 12:37 PM	#13 (permalink)
mholt DNOA Member Join Date: May 2004 Posts: 5,040	You want to make sure that $HTTP_POST_VARS['password'] is equal to $password? Here: Code: if (isset($HTTP_POST_VARS['submit])) { if ($HTTP_POST_VARS['password'] != $password) { echo('The passwords do not match.'); } } That what you mean?

08-02-2005, 08:31 PM	#15 (permalink)
luxinterior Senior Member Join Date: Jul 2004 Location: Kizmiaz Posts: 1,091	Your've got the variable $password in single quotation marks making it a string literal as in no longer a variable but the string $password. Remove them and it should be ok. Lux __________________ 1 Cent Web Hosting @ Online HostGatorVoucher.com Adsense Hack for Vbulletin - Fully 3.6 Compatible ForexArea.com Free E-Course in Programming EA's

08-03-2005, 10:31 AM	THREAD STARTER #16 (permalink)
unknowngiver Senior Member Join Date: May 2005 Location: Ontario Canada Posts: 3,088	Still the same here is the code now Code: $password='zubair' if($HTTP_POST_VARS['submit']) { if($HTTP_POST_VARS['password'] == $password) { if(!$HTTP_POST_VARS['name']) { echo "You must enter a name"; exit; } if(!$HTTP_POST_VARS['news']) { echo "You must enter some news"; exit; } __________________ Simplifying Engineering \|\| $$ Currency Converter $$ Julsh - Community/Dating Website \|\| Free Image hosting Fresh Proxies \|\| Random Proxy \|\| Troll Board

08-05-2005, 09:23 AM	THREAD STARTER #17 (permalink)
unknowngiver Senior Member Join Date: May 2005 Location: Ontario Canada Posts: 3,088	anyone wana give it a try please __________________ Simplifying Engineering \|\| $$ Currency Converter $$ Julsh - Community/Dating Website \|\| Free Image hosting Fresh Proxies \|\| Random Proxy \|\| Troll Board

Currently Active Users Viewing This Thread: 1 (0 members and 1 guests)

08-05-2005, 11:24 AM	#18 (permalink)
mholt DNOA Member Join Date: May 2004 Posts: 5,040	You have to close two more curly brackets at the end.

08-05-2005, 11:45 AM	#19 (permalink)
Amnezia Professional Monkey Join Date: Jul 2005 Location: Escaped from the zoo Posts: 907	you missing a semi colon at the end of the first line __________________ Webmaster Words

08-05-2005, 12:14 PM	#20 (permalink)
mholt DNOA Member Join Date: May 2004 Posts: 5,040	Yes!!! Amnezia wins the prize! ^_^ (Lol my post was just a test to see if it'd distract you )

08-05-2005, 10:11 PM	#22 (permalink)
Refrozen Account Closed Join Date: Jun 2005 Posts: 745	. means append \r\n means Winodws newline

08-07-2005, 09:34 PM	THREAD STARTER #23 (permalink)
unknowngiver Senior Member Join Date: May 2005 Location: Ontario Canada Posts: 3,088	Help didnt work guys __________________ Simplifying Engineering \|\| $$ Currency Converter $$ Julsh - Community/Dating Website \|\| Free Image hosting Fresh Proxies \|\| Random Proxy \|\| Troll Board

08-07-2005, 10:10 PM	#24 (permalink)
Eric Senior Member Join Date: Mar 2005 Posts: 4,948	nvmd Just changed a couple of things.. Modified from my original post. PHP Code: `<?php $password = 'zubair'; if($HTTP_POST_VARS['submit']) { if($HTTP_POST_VARS['password'] == $password) { if(!$HTTP_POST_VARS['name']) { echo "You must enter a name"; exit; } if(!$HTTP_POST_VARS['news']) { echo "You must enter some news"; exit; } } ?>`

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