[php] I am having htaccess, gd2, and header problems, please help.

bliss · 12-10-2006, 07:20 PM

I have a problem with a script doubling a count of the view's of a image when I display it. When I take ImagePNG($img); out of the script. The counter only counts it as one hit, but when I have imagepng($img) it shows it as two hits. I am very confused as to why it might be doing this. I do have headers in the file that make the file non-cache'd by the browser. Do you think it is counting it twice, because it is revalidating the image?

Here is the code.

Code:

<Files view>
	SetHandler application/x-httpd-php
</Files>

Code:

	
<?php
 session_start();
 
 include('connect_mysql.php');
 mysql_query("update bannerstats set exposures=exposures+1'");

 $bannerurl = "http://site.com/image.png";
 $imagestuff = @getimagesize($bannerurl);
 $imagetype = $imagestuff[2];
 if ( $imagetype == '2') { $img = imagecreatefromjpeg($bannerurl); }
 if ( $imagetype == '3') { $img = imagecreatefrompng($bannerurl); imageSaveAlpha($img, true); }

  header("Expires: Mon, 26 Jul 1997 05:00:00 GMT");
  header("Last-Modified: " . gmdate("D, d M Y H:i:s") . " GMT");
  header("Cache-Control: no-store, no-cache, must-revalidate");
  header("Cache-Control: post-check=0, pre-check=0", false);
  header("Pragma: no-cache");
  header( "Content-type: image/png");
//exit;
  ImagePNG($img);
  ImageDestroy($img);
?>

If I uncomment exit then it will update exposures by one. If I show the image ,imagepng($img), and comment the exit it will update exposures by two.
????: NamePros.com http://www.namepros.com/code/267683-php-i-am-having-htaccess-gd2.html

Why?

How can I stop this from happening?

lee101 · 12-12-2006, 10:59 AM

I'm no expert with the GD image library but won't using exit; quit the script, therefore stopping any code after it from being executed? What happens if you put exit; at the very end of the script?

bliss · 12-12-2006, 04:26 PM

I am using a session work around, but it is not that the script is not exiting. It is that the browser is loading the script twice. So, exit will not work with it. I think it has something to do with the headers and how i have it revalidate the file instead of running it from the cache'd copy. Which I can't get around cause I need it to show a different banner each time.

keesj · 12-22-2006, 11:24 AM

You can try a couple of things. Firstly, try removing must-revalidate from your header. If that doesn't work, add it again and do the following:

Remove the cache stuff in your script. And when displaying the file on a html page to the following:

Code:

<img src="script.php?<?php time() ?>" />

This way every request is unique and therefor the browser won't use a cached file.
????: NamePros.com http://www.namepros.com/showthread.php?t=267683

Or you can increment your stats by .5

You can also get into headers and figure out what really is causing the problem:
http://www.w3.org/Protocols/rfc2616/rfc2616-sec13.html

bliss · 12-22-2006, 04:23 PM

Can't cause the link to the file is going to be a static link and I need it to display dynamic images.

beaver6813 · 12-29-2006, 11:40 AM

Try using

PHP Code:

  ob_start();

at the beginning of your file above session_start(); that will buffer everything until its all finished executing. I used the same kinda things as you're trying to do on my site http://www.diggfile.com which ill be releasing the source for soon.

jerometan · 12-30-2006, 07:51 PM

This shouldn't be in the CODE forum anyways - it should be in the parent forum.

12-10-2006, 07:20 PM	THREAD STARTER #1 (permalink)
bliss NamePros Regular Join Date: Dec 2005 Posts: 950	[php] I am having htaccess, gd2, and header problems, please help. I have a problem with a script doubling a count of the view's of a image when I display it. When I take ImagePNG($img); out of the script. The counter only counts it as one hit, but when I have imagepng($img) it shows it as two hits. I am very confused as to why it might be doing this. I do have headers in the file that make the file non-cache'd by the browser. Do you think it is counting it twice, because it is revalidating the image? Here is the code. Code: <Files view> SetHandler application/x-httpd-php </Files> Code: <?php session_start(); include('connect_mysql.php'); mysql_query("update bannerstats set exposures=exposures+1'"); $bannerurl = "http://site.com/image.png"; $imagestuff = @getimagesize($bannerurl); $imagetype = $imagestuff[2]; if ( $imagetype == '2') { $img = imagecreatefromjpeg($bannerurl); } if ( $imagetype == '3') { $img = imagecreatefrompng($bannerurl); imageSaveAlpha($img, true); } header("Expires: Mon, 26 Jul 1997 05:00:00 GMT"); header("Last-Modified: " . gmdate("D, d M Y H:i:s") . " GMT"); header("Cache-Control: no-store, no-cache, must-revalidate"); header("Cache-Control: post-check=0, pre-check=0", false); header("Pragma: no-cache"); header( "Content-type: image/png"); //exit; ImagePNG($img); ImageDestroy($img); ?> If I uncomment exit then it will update exposures by one. If I show the image ,imagepng($img), and comment the exit it will update exposures by two. ????: NamePros.com http://www.namepros.com/code/267683-php-i-am-having-htaccess-gd2.html Why? How can I stop this from happening? Last edited by bliss; 12-10-2006 at 09:35 PM.

12-12-2006, 10:59 AM	#2 (permalink)
lee101 NamePros Regular Join Date: Mar 2006 Location: United Kingdom Posts: 413 Follow @leefindlow	I'm no expert with the GD image library but won't using exit; quit the script, therefore stopping any code after it from being executed? What happens if you put exit; at the very end of the script? __________________ Linux Screenshots

12-22-2006, 11:24 AM	#4 (permalink)
keesj NamePros Member Join Date: Dec 2006 Posts: 122	You can try a couple of things. Firstly, try removing must-revalidate from your header. If that doesn't work, add it again and do the following: Remove the cache stuff in your script. And when displaying the file on a html page to the following: Code: <img src="script.php?<?php time() ?>" /> This way every request is unique and therefor the browser won't use a cached file. ????: NamePros.com http://www.namepros.com/showthread.php?t=267683 Or you can increment your stats by .5 You can also get into headers and figure out what really is causing the problem: http://www.w3.org/Protocols/rfc2616/rfc2616-sec13.html __________________ Check out some Available Domains I posted.

12-29-2006, 11:40 AM	#6 (permalink)
beaver6813 NamePros Regular Join Date: May 2005 Location: England Posts: 390 Follow @beaver6813	Try using PHP Code: `ob_start();` at the beginning of your file above session_start(); that will buffer everything until its all finished executing. I used the same kinda things as you're trying to do on my site http://www.diggfile.com which ill be releasing the source for soon. __________________ -Beaver6813.com - Web Developer Extraordinaire!

12-30-2006, 07:51 PM	#7 (permalink)
jerometan NamePros Regular Join Date: Feb 2006 Posts: 584	This shouldn't be in the CODE forum anyways - it should be in the parent forum. __________________ Budget NP$ Hosting - Affordable CPanel Hosting! [ Click Here For Sales/Support ] 50NP Proxy Hosting \| URLToUs \| Fast Reliable Budget Host! [ Click Here For Sales/Support ]

12-12-2006, 04:26 PM	THREAD STARTER #3 (permalink)
bliss NamePros Regular Join Date: Dec 2005 Posts: 950	I am using a session work around, but it is not that the script is not exiting. It is that the browser is loading the script twice. So, exit will not work with it. I think it has something to do with the headers and how i have it revalidate the file instead of running it from the cache'd copy. Which I can't get around cause I need it to show a different banner each time.

12-22-2006, 04:23 PM	THREAD STARTER #5 (permalink)
bliss NamePros Regular Join Date: Dec 2005 Posts: 950	Can't cause the link to the file is going to be a static link and I need it to display dynamic images.

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