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-   -   I get this error!!! (http://www.namepros.com/programming/485488-i-get-this-error.html)

mwasiqansari 06-24-2008 12:00 PM

I get this error!!!
 
i have this code, i tried to put it with my code but it get some error.

Code:
<? include 'connect.php'; $tbl_name="news"; $adjacents = 3; $query = "SELECT COUNT(*) as num FROM $tbl_name"; $total_pages = mysql_fetch_array(mysql_query($query)); $total_pages = $total_pages[num]; $targetpage = "news.php"; $limit = 2; $page = $_GET['page']; if($page) $start = ($page - 1) * $limit; else $start = 0; $sql = "SELECT * FROM $tbl_name order by a_id asc LIMIT $start, $limit"; $result = mysql_query($sql); if ($page == 0) $page = 1; $prev = $page - 1; $next = $page + 1; $lastpage = ceil($total_pages/$limit); $lpm1 = $lastpage - 1; $pagination = ""; if($lastpage > 1) { $pagination .= "<div class=\"pagination\">"; //previous button if ($page > 1) $pagination.= "<a href=\"$targetpage?page=$prev\">« previous</a>"; else $pagination.= "<span class=\"disabled\">« previous</span>"; //pages if ($lastpage < 7 + ($adjacents * 2)) //not enough pages to bother breaking it up { for ($counter = 1; $counter <= $lastpage; $counter++) { if ($counter == $page) $pagination.= "<span class=\"current\">$counter</span>"; else $pagination.= "<a href=\"$targetpage?page=$counter\">$counter</a>"; } } elseif($lastpage > 5 + ($adjacents * 2)) //enough pages to hide some { //close to beginning; only hide later pages if($page < 1 + ($adjacents * 2)) { for ($counter = 1; $counter < 4 + ($adjacents * 2); $counter++) { if ($counter == $page) $pagination.= "<span class=\"current\">$counter</span>"; else $pagination.= "<a href=\"$targetpage?page=$counter\">$counter</a>"; } $pagination.= "..."; $pagination.= "<a href=\"$targetpage?page=$lpm1\">$lpm1</a>"; $pagination.= "<a href=\"$targetpage?page=$lastpage\">$lastpage</a>"; } //in middle; hide some front and some back elseif($lastpage - ($adjacents * 2) > $page && $page > ($adjacents * 2)) { $pagination.= "<a href=\"$targetpage?page=1\">1</a>"; $pagination.= "<a href=\"$targetpage?page=2\">2</a>"; $pagination.= "..."; for ($counter = $page - $adjacents; $counter <= $page + $adjacents; $counter++) { if ($counter == $page) $pagination.= "<span class=\"current\">$counter</span>"; else $pagination.= "<a href=\"$targetpage?page=$counter\">$counter</a>"; } $pagination.= "..."; $pagination.= "<a href=\"$targetpage?page=$lpm1\">$lpm1</a>"; $pagination.= "<a href=\"$targetpage?page=$lastpage\">$lastpage</a>"; } //close to end; only hide early pages else { $pagination.= "<a href=\"$targetpage?page=1\">1</a>"; $pagination.= "<a href=\"$targetpage?page=2\">2</a>"; $pagination.= "..."; for ($counter = $lastpage - (2 + ($adjacents * 2)); $counter <= $lastpage; $counter++) { if ($counter == $page) $pagination.= "<span class=\"current\">$counter</span>"; else $pagination.= "<a href=\"$targetpage?page=$counter\">$counter</a>"; } } } //next button if ($page < $counter - 1) $pagination.= "<a href=\"$targetpage?page=$next\">next »</a>"; else $pagination.= "<span class=\"disabled\">next »</span>"; $pagination.= "</div>\n"; } ?> <? while($row = mysql_fetch_array($result)) { $id = $row["a_id"]; $title = ucwords($row["title"]); $news = $row["short"]; $date = $row["a_date"]; echo $short; echo "<br>"; } ?> <?=$pagination?>


the ERROR is :

Notice: Use of undefined constant num - assumed 'num'

$total_pages = $total_pages[num];

i dont know what is that mean??

Bruce_KD 06-24-2008 12:15 PM

It isn't an error, just a "Notice" :)

It's really $total_pages['num'] (Note, "num" is a String)
In php, you can definite constants
Variables are prefixed with the $, but constants have no prefix.
Fortunately, php is smart enough to realize that in $total_pages[num], since you have no constant named num, you must mean the string 'num'.


Bruce

itnashvillecom 06-25-2008 05:12 AM

When you do not use quotes:

$var[num]

it is assumed to be an array.

xrvel 06-25-2008 06:15 AM

Bruce, you are correct :bingo: Use $total_pages['num'] instead of $total_pages[num]


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