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Dave in Carthage 12-30-2007 06:09 PM

Amazing Math Trick
 
Here is a math trick so unbelievable that it will stump you.

1. Grab a calculator. (you won't be able to do this one in your head)
2. Key in the first three digits of your phone number (NOT the area code)
3. Multiply by 80
4. Add 1
5. Multiply by 250
6. Add the last 4 digits of your phone number
7. Add the last 4 digits of your phone number again.
8. Subtract 250
9. Divide number by 2

Do you recognize the answer?

johname 12-30-2007 08:16 PM

it works lol

SecondVersion 12-30-2007 08:20 PM

Neat.

deet 12-30-2007 08:38 PM

lol, now that was neat. :)

Frikkle 12-30-2007 08:47 PM

Whoah...now why does that work?

x is first few digits, y is last few digits

80x+1
(80x+1)*250 = 20000x+250
20000x+250+y
20000x+250+y+y=20000x+250+2y
20000x+250+2y-250=20000x+2y
(20000x+2y)/2=10000x+y

That makes sense, huh. Given that the phone number is the last four digits plus 10,000 times the first three digits (because it is 4 decimal places over).

-Frikkle :tu:

-Nick- 12-30-2007 09:28 PM

WOW that was nice :)

x = (x1 * 80) + 1 * 250 + x2 + x2 - 250 / 2

networkmsia 12-30-2007 09:31 PM

wow cool. Thanks for sharing :)

Anthony 12-30-2007 09:46 PM

Originally Posted by Frikkle
80x+1
(80x+1)*250 = 20000x+250
20000x+250+y
20000x+250+y+y=20000x+250+2y
20000x+250+2y-250=20000x+2y
(20000x+2y)/2=10000x+y



Oh, why didn't you just say that in the first place? :lol:

iulianh 12-31-2007 04:00 AM

:lol: works.

tekz999 12-31-2007 05:58 AM

Wow. It even works with a hong kong phone number.

Dave in Carthage 12-31-2007 08:48 AM

x = (x1 * 80) + 1 * 250 + x2 + x2 - 250 / 2

Is there a shorter mathematical expression for this? Or is that the shortest possible?

unknowngiver 03-06-2008 08:46 AM

wont work if either in your last 4 digits, or the first 3 digits...the FIRST number is "0"
for example my last 4 digits were "0486" so it didnt work

Dan 03-06-2008 05:39 PM

Originally Posted by dgridley
x = (x1 * 80) + 1 * 250 + x2 + x2 - 250 / 2

Is there a shorter mathematical expression for this? Or is that the shortest possible?

This one is shorter: x = your phone number.


Originally Posted by unknowngiver
wont work if either in your last 4 digits, or the first 3 digits...the FIRST number is "0"
for example my last 4 digits were "0486" so it didnt work

You did something wrong. (I tried it with xxx-0486 and it worked.) The only way it wouldn't "work" would be if the very first number is 0 which it can't be (I think).

allabout42 03-06-2008 09:02 PM

That's Pretty Cool.

If you let x = first digits of phone number, y = last 4 digits of phone number.
[(80x + 1)250 + 2y - 250]/2
[20000x + 250 -250 + 2y]/2
[20000x + 2y]/2
10000x + y

So this does make sense, since you are effectively shifting your x value by a factor of 10000 or 4 zero places. This is similar to how a computer does addition and subtraction back in the old days when memory was at a premium.

Of course any leading zeros in the x place would make this equation produce the wrong result. Maybe that's why all phone numbers don't begin with zeros. :hehe:

Originally Posted by dgridley
Here is a math trick so unbelievable that it will stump you.

1. Grab a calculator. (you won't be able to do this one in your head)
2. Key in the first three digits of your phone number (NOT the area code)
3. Multiply by 80
4. Add 1
5. Multiply by 250
6. Add the last 4 digits of your phone number
7. Add the last 4 digits of your phone number again.
8. Subtract 250
9. Divide number by 2

Do you recognize the answer?


lpxxfaintxx 03-06-2008 09:04 PM

Pretty cool! Gave me a chuckle.

commes 03-06-2008 09:45 PM

And who would find the time to discover an equation like this?

-Commes

htmlindex 03-06-2008 11:20 PM

Nice! :)


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